我正在使用数据表。我有一个响应，我需要在datatable中显示。现在，为了测试，我采用了json，我无法从中提取值？
我检查过jquery.map，但我没有得到如何使用它。
这是我的json -
var json = [{"_attr":{"col_Decision":{"_value":"Count"},"col1":{"_value":"2,698"},"col2":{"_value":"1,724"},"col3":{"_value":"4,422"},"col4":{"_value":"1,457"},"col5":{"_value":"1,047"},"col6":{"_value":"2,504"},"col7":{"_value":"1,241"},"col8":{"_value":677},"col9":{"_value":"1,918"}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Avg Days"},"col1":{"_value":4},"col2":{"_value":2.2},"col3":{"_value":3.3},"col4":{"_value":4},"col5":{"_value":1.9},"col6":{"_value":3.1},"col7":{"_value":4},"col8":{"_value":2.8},"col9":{"_value":3.5}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Goal Met %"},"col1":{"_value":84.2},"col2":{"_value":90.8},"col3":{"_value":86.8},"col4":{"_value":79.9},"col5":{"_value":91.1},"col6":{"_value":84.6},"col7":{"_value":89.4},"col8":{"_value":90.4},"col9":{"_value":89.7}},"_text":[null]}]
现在我需要col_Decision，col1，col2，col3，... col9的值。共有3行。所以它在回复中将是3次。
它可能很容易，但我没有得到它。
代码失败 -
var itemvalue = arrayObj.data[0].itemlist[0].item;
const data = JSON.stringify(itemvalue);
// var myJsonString = JSON.stringify(itemvalue);
//console.log(myJsonString);
console.log(data);
//loadDataTable(data);
const rows = data.map(
({_attr}) => Object.keys(_attr).map ( key => _attr[key]._value )
);
console.log(rows);
答案 0 :(得分：2)
使用JS，您可能需要迭代内部的每个对象的属性。 在迭代中，您可能需要这样：
var aAssignColumnData = [];
for (var iIndex in json) {
// We'll assign this variable to the [_attr] inside [json] object
aAssignColumnData.push(json[iIndex]._attr);
}
// Now, [aAssignColumnData] has the object values containing the [_attr] object values.
for (var iColumnIndex in aAssignColumnData) {
if (aAssignColumnData.hasOwnProperty(iColumnIndex) === true) {
// e.g _attr[0] / _attr[1] / _attr[2]
var oColumnNames = aAssignColumnData[iColumnIndex];
// Then we'll get the number of properties inside the [json's _attr] values
var iLength = Object.keys(oColumnNames).length; // e.g 10, since 3 of your [_attr] had 10 objects inside.
// Then we'll iterate each of them using {for}
for (var iCtr = 0; iCtr < iLength; iCtr++) {
if (typeof oColumnNames['col' + iCtr] === 'object') {
console.log(oColumnNames['col' + iCtr]['_value']);
} else {
// This is to retrieve the ['col_Decision'] property
if (typeof oColumnNames['col_Decision'] === 'object') {
console.log(oColumnNames['col_Decision']['_value']);
}
}
}
}
}
以下是jsfiddle以供进一步参考：https://jsfiddle.net/8b99z0tL/
希望这有助于您的情况。
答案 1 :(得分：1)
也许是这样的？它使用map和es2015 lambas。
Array.from(Array(3)).map((a, i) => {
return Array.from(Array(9)).map((b, j) => {
return json[i]._attr["col"+(j+1)]._value;
});
});
你也可以使用普通的嵌套循环：
var result = [];
for(i=0; i<3; i++){
var row = []
for(j=1; j<=9; j++){
row.push(json[i]._attr["col"+j])._value;
}
result.push(row)
}
答案 2 :(得分：0)
您可以使用此ES6代码：
data.map( ({_attr}) => Object.keys(_attr).map ( key => _attr[key]._value ) );
const data = [{"_attr":{"col_Decision":{"_value":"Count"},"col1":{"_value":"2,698"},"col2":{"_value":"1,724"},"col3":{"_value":"4,422"},"col4":{"_value":"1,457"},"col5":{"_value":"1,047"},"col6":{"_value":"2,504"},"col7":{"_value":"1,241"},"col8":{"_value":677},"col9":{"_value":"1,918"}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Avg Days"},"col1":{"_value":4},"col2":{"_value":2.2},"col3":{"_value":3.3},"col4":{"_value":4},"col5":{"_value":1.9},"col6":{"_value":3.1},"col7":{"_value":4},"col8":{"_value":2.8},"col9":{"_value":3.5}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Goal Met %"},"col1":{"_value":84.2},"col2":{"_value":90.8},"col3":{"_value":86.8},"col4":{"_value":79.9},"col5":{"_value":91.1},"col6":{"_value":84.6},"col7":{"_value":89.4},"col8":{"_value":90.4},"col9":{"_value":89.7}},"_text":[null]}];
const rows = data.map(
({_attr}) => Object.keys(_attr).map ( key => _attr[key]._value )
);
console.log(rows);
注意：不要调用变量 json ，因为它不是：它是一个JavaScript对象。如果它是一个字符串，它将是JSON。
答案 3 :(得分：0)
尝试以下方法：
var json = [{"_attr":{"col_Decision":{"_value":"Count"},"col1":{"_value":"2,698"},"col2":{"_value":"1,724"},"col3":{"_value":"4,422"},"col4":{"_value":"1,457"},"col5":{"_value":"1,047"},"col6":{"_value":"2,504"},"col7":{"_value":"1,241"},"col8":{"_value":677},"col9":{"_value":"1,918"}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Avg Days"},"col1":{"_value":4},"col2":{"_value":2.2},"col3":{"_value":3.3},"col4":{"_value":4},"col5":{"_value":1.9},"col6":{"_value":3.1},"col7":{"_value":4},"col8":{"_value":2.8},"col9":{"_value":3.5}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Goal Met %"},"col1":{"_value":84.2},"col2":{"_value":90.8},"col3":{"_value":86.8},"col4":{"_value":79.9},"col5":{"_value":91.1},"col6":{"_value":84.6},"col7":{"_value":89.4},"col8":{"_value":90.4},"col9":{"_value":89.7}},"_text":[null]}];
var res = json.map(function(value){
return Object.keys(value._attr).map(function(e) {
var obj = {};
obj[e]=value._attr[e];
return obj;
});
});
console.log(res)
答案 4 :(得分：0)
<script>
var json = [{"_attr":{"col_Decision":{"_value":"Count"},"col1":{"_value":"2,698"},"col2":{"_value":"1,724"},"col3":{"_value":"4,422"},"col4":{"_value":"1,457"},"col5":{"_value":"1,047"},"col6":{"_value":"2,504"},"col7":{"_value":"1,241"},"col8":{"_value":677},"col9":{"_value":"1,918"}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Avg Days"},"col1":{"_value":4},"col2":{"_value":2.2},"col3":{"_value":3.3},"col4":{"_value":4},"col5":{"_value":1.9},"col6":{"_value":3.1},"col7":{"_value":4},"col8":{"_value":2.8},"col9":{"_value":3.5}},"_text":[null]},{"_attr":{"col_Decision":{"_value":"Goal Met %"},"col1":{"_value":84.2},"col2":{"_value":90.8},"col3":{"_value":86.8},"col4":{"_value":79.9},"col5":{"_value":91.1},"col6":{"_value":84.6},"col7":{"_value":89.4},"col8":{"_value":90.4},"col9":{"_value":89.7}},"_text":[null]}]
for(var i=0;i<json.length;i++){
var keyNames,valueObj;
var attrObj=json[i]._attr;
for (keyNames in attrObj) {
valueObj=attrObj[keyNames];
console.log(keyNames+" : "+valueObj._value);
}
}
</script>
keyNames会为您提供密钥的名称，valueObj._value会为您提供该特定密钥的值。