Question

我有一个数组，即$ checked_posts，看起来像 -

Array
(
    [0] => 13
    [1] => 15
)

此数组包含所选帖子的ID 我从数据库中获取数据，如 -

$q=mysql_query("select ID,post_title from sa_posts
                where post_author='".$this->session->userdata('admin_id')."'
                and post_type='post'
                and post_status='publish'
                order by ID desc
              ");

此查询获取ID和post_title
我想比较数组$ checked_posts值（id）和select查询获取id 如果两者都匹配，那么我想提前显示该记录，如果没有，则应在所有选择的记录之后显示这些记录假设我的$ checked_post数组包含 -

 Array
(
    [0] => 13
    [1] => 15
)

和我的选择查询获取记录（id's），如15,13,20,25,32，在这种情况下，我必须首先显示id匹配的记录，然后我想显示所有不匹配的元素。
到目前为止我已经尝试过了 -

$q=mysql_query("select ID,post_title from sa_posts
                where   post_author='".$this->session->userdata('admin_id')."'
                and post_type='post'
                and post_status='publish'
                order by ID desc
               ");                           
                while($p=mysql_fetch_array($q))
                {
                    if(in_array($p['ID'],$checked_posts))
                    {
                           $check_post='checked'; // I want to display all these elements firstly and later all unmatched elements.
                        }
                        else
                        {
                           $check_post='';
                        }
echo "<li class='menu_post_list' id='".$m_n."' style='list-style:none;display:".$disp_post."'>
<input type='checkbox' value='".$p['ID']."' class='menu_list_post' $check_post> ".$p['post_title']."</li>";  
                 }

请帮帮我谢谢。

Answer 1

您可以通过将检查放入查询的ORDER BY子句来完成此操作。

$checked_str = implode(',', $checked_posts);

$q=mysql_query("select ID,post_title from sa_posts
            where   post_author='".$this->session->userdata('admin_id')."'
            and post_type='post'
            and post_status='publish'
            order by ID IN ($checked_posts) DESC, ID desc
           ");

您还可以通过将其添加到查询结果中来避免在PHP代码中执行in_array()测试：

$q=mysql_query("select ID,post_title, ID IN ($checked_posts) as checked
            from sa_posts
            where   post_author='".$this->session->userdata('admin_id')."'
            and post_type='post'
            and post_status='publish'
            order by checked DESC, ID desc
           ");

然后PHP代码可以使用

$check_post = $p['checked'] ? 'checked' : '';

Answer 2

你可以加入已检查的ID，因为它们来自db，不需要php操作

select ID,post_title from sa_posts 
        JOIN someOtherTable ON sa_posts.ID=someoOtherTable.checkedIds
                where   post_author='".$this->session->userdata('admin_id')."'
                and post_type='post'
                and post_status='publish'
                order by ID desc

根据php中的条件按顺序显示数组元素

2 个答案: