我正在努力提取RedHat漏洞信息而且我被困在sql查询中:)基本上我有2个表（cve，勘误表），其中保存数据，第三个（引用）是带有ID的参考表从表errata和cve。
我想要提取的是来自两个表的信息，如下所示：
name_from_errata name_from_cve severity_from_errata releasedata_from_errata
RHSA-2017:0837 CVE-2017-5208 important 2017-03-23...
RHSA-2017:0837 CVE-2017-5332 moderate 2017-03-23...
RHSA-2017:0837 CVE-2017-5333 important ............
RHSA-2017:0837 CVE-2017-6009 important ............
.........................
谢谢！
马里奥
例如，此链接列出了6个漏洞 RedHat Advisory sample
CVE-2017-5208
CVE-2017-5332
CVE-2017-5333
CVE-2017-6009
CVE-2017-6010
CVE-2017-6011
Sqlite3数据库@ cvrf
[localhost cvrf]$ sqlite3 cvrf.db
sqlite> .headers on
sqlite> .mode column
sqlite> .tables
cve errata package relationship`
sqlite> .schema cve
CREATE TABLE "cve" ("id" INTEGER NOT NULL PRIMARY KEY, "name" VARCHAR(255) NOT NULL, "severity" VARCHAR(255), "cvss_score" VARCHAR(255), "publicdate" DATETIME);
CREATE UNIQUE INDEX "cve_name" ON "cve" ("name");`
sqlite> .schema errata
CREATE TABLE "errata" ("id" INTEGER NOT NULL PRIMARY KEY, "name" VARCHAR(255) NOT NULL, "severity" VARCHAR(255), "releasedate" DATETIME);
CREATE UNIQUE INDEX "errata_name" ON "errata" ("name");`
sqlite> .schema relationship
CREATE TABLE "relationship" ("id" INTEGER NOT NULL PRIMARY KEY, "errata_id" INTEGER NOT NULL, "cve_id" INTEGER NOT NULL, FOREIGN KEY ("errata_id") REFERENCES "errata" ("id"), FOREIGN KEY ("cve_id") REFERENCES "cve" ("id"));
CREATE INDEX "relationship_errata_id" ON "relationship" ("errata_id");
CREATE INDEX "relationship_cve_id" ON "relationship" ("cve_id");
CREATE UNIQUE INDEX "relationship_errata_id_cve_id" ON "relationship" ("errata_id", "cve_id");
获取过去2天的建议清单（我需要最后一天，但今天没有建议）
sqlite> SELECT * FROM errata WHERE releasedate > (SELECT DATETIME('now', '-2 day'));
id name severity releasedate
---------- -------------- ---------- --------------------
2722 RHSA-2017:0837 important 2017-03-23T00:21:00Z
2723 RHSA-2017:0838 moderate 2017-03-23T02:35:00Z
2724 RHSA-2017:0484 moderate 2017-03-23T04:59:00Z
2725 RHSA-2017:0494 moderate 2017-03-23T04:59:00Z
2726 RHSA-2017:0495 moderate 2017-03-23T05:04:00Z
2727 RHSA-2017:0486 moderate 2017-03-23T05:04:00Z
获取与勘误表关联的ID列表是＆＃39; 2722＆＃39;
sqlite> select cve_id from relationship where errata_id='2722';
cve_id
----------
5002
5003
5004
5005
5006
5007
获取与勘误名称RHSA-2017相关的cve名称列表：0837（勘误表编号5002）
qlite> select * from cve where id='5002';
id name severity cvss_score publicdate
---------- ------------- ---------- ---------- --------------------
5002 CVE-2017-5208 important NULL 2017-01-08T00:00:00Z
sqlite> select * from cve where id='5003';
id name severity cvss_score publicdate
---------- ------------- ---------- ---------- --------------------
5003 CVE-2017-5332 moderate NULL 2017-01-10T00:00:00Z
sqlite> select * from cve where id='5004';
id name severity cvss_score publicdate
---------- ------------- ---------- ---------- --------------------
5004 CVE-2017-5333 important NULL 2017-01-10T00:00:00Z
sqlite> select * from cve where id='5005';
id name severity cvss_score publicdate
---------- ------------- ---------- ---------- --------------------
5005 CVE-2017-6009 important NULL 2017-02-16T00:00:00Z
sqlite> select * from cve where id='5006';
id name severity cvss_score publicdate
---------- ------------- ---------- ---------- --------------------
5006 CVE-2017-6010 moderate NULL 2017-02-16T00:00:00Z
sqlite> select * from cve where id='5007';
id name severity cvss_score publicdate
---------- ------------- ---------- ---------- --------------------
5007 CVE-2017-6011 moderate NULL 2017-02-16T00:00:00Z
答案 0 :(得分：0)
加入表格：
SELECT e.name, c.name, e.severity, e.releasedate
FROM errata e
JOIN relationship r ON e.id = r.errata_id
JOIN cve c ON c.id = r.cve_id
WHERE e.releasedate > DATETIME('now', '-2 day')