我目前如何从进程列表中提取图标而不是文件名?截至目前,这通过打开表格对话框,他们点击一个文件,然后将其添加到带有图标的listView。怎么做我只是获取进程图标并在listView中显示它们?
[StructLayout(LayoutKind.Sequential)]
public struct SHFILEINFO
{
public IntPtr hIcon;
public IntPtr iIcon;
public uint dwAttributes;
[MarshalAs(UnmanagedType.ByValTStr, SizeConst = 260)]
public string szDisplayName;
[MarshalAs(UnmanagedType.ByValTStr, SizeConst = 80)]
public string szTypeName;
};
class Win32
{
public const uint SHGFI_ICON = 0x100;
public const uint SHGFI_LARGEICON = 0x0; // 'Large icon
public const uint SHGFI_SMALLICON = 0x1; // 'Small icon
[DllImport("shell32.dll")]
public static extern IntPtr SHGetFileInfo(string pszPath,
uint dwFileAttributes,
ref SHFILEINFO psfi,
uint cbSizeFileInfo,
uint uFlags);
}
private int nIndex = 0;
private void materialFlatButton13_Click_1(object sender, EventArgs e)
{
IntPtr hImgSmall; //the handle to the system image list
IntPtr hImgLarge; //the handle to the system image list
string fName; // 'the file name to get icon from
SHFILEINFO shinfo = new SHFILEINFO();
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\temp\\";
openFileDialog1.Filter = "All files (*.*)|*.*";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
listView1.SmallImageList = imageList1;
listView1.LargeImageList = imageList1;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
fName = openFileDialog1.FileName;
//Use this to get the small Icon
hImgSmall = Win32.SHGetFileInfo(fName, 0, ref shinfo,
(uint)Marshal.SizeOf(shinfo),
Win32.SHGFI_ICON |
Win32.SHGFI_SMALLICON);
System.Drawing.Icon myIcon =
System.Drawing.Icon.FromHandle(shinfo.hIcon);
imageList1.Images.Add(myIcon);
//Add file name and icon to listview
listView1.Items.Add(fName, nIndex++);
}
答案 0 :(得分:2)
您可以使用Win32_Process
上的WMI查询查找流程信息,并使用ExecutablePath
查找流程的可执行路径。然后,您可以使用Icon.ExtractAssociatedIcon
提取流程的关联图标:
示例强>
在表单上放置ImageList
并将其ColorDepth
设置为Depth32Bit
,将ImageSize
设置为32,32
。在表单上放置ListView
,并将其LargImageList
设置为您在第一步中创建的imageList1
。
添加对System.Management.dll
的引用并添加using System.Management;
并使用以下代码填充listView1
图标:
var query = "SELECT ProcessId, Name, ExecutablePath FROM Win32_Process";
using (var searcher = new ManagementObjectSearcher(query))
using (var results = searcher.Get())
{
var processes = results.Cast<ManagementObject>().Select(x => new
{
ProcessId = (UInt32)x["ProcessId"],
Name = (string)x["Name"],
ExecutablePath = (string)x["ExecutablePath"]
});
foreach (var p in processes)
{
if (System.IO.File.Exists(p.ExecutablePath))
{
var icon = Icon.ExtractAssociatedIcon(p.ExecutablePath);
var key = p.ProcessId.ToString();
this.imageList1.Images.Add(key, icon.ToBitmap());
this.listView1.Items.Add(p.Name, key);
}
}
}
然后你会得到这样的结果:
答案 1 :(得分:0)
见这里:C#: How to get the full path of running process?
foreach(var process in Process.GetProcesses()){
string fullPath = process.MainModule.FileName;
// do your stuff here
}
您可以将其替换为现有代码。或者,根据你现在所做的事情量身定做。
编辑:添加代码以获取进程
答案 2 :(得分:0)
(仅限System.Diagnostics
)
这将获得主模块的图标(exe文件)。如果访问和目标进程的体系结构不同,它也将起作用:
var icon = Process.GetProcessById(1234).GetIcon()
使用扩展方法:
public static class ProcessExtensions {
[DllImport("Kernel32.dll")]
private static extern uint QueryFullProcessImageName([In] IntPtr hProcess, [In] uint dwFlags, [Out] StringBuilder lpExeName, [In, Out] ref uint lpdwSize);
public static string GetMainModuleFileName(this Process process, int buffer = 1024) {
var fileNameBuilder = new StringBuilder(buffer);
uint bufferLength = (uint)fileNameBuilder.Capacity + 1;
return QueryFullProcessImageName(process.Handle, 0, fileNameBuilder, ref bufferLength) != 0 ?
fileNameBuilder.ToString() :
null;
}
public static Icon GetIcon(this Process process) {
try {
string mainModuleFileName = process.GetMainModuleFileName();
return Icon.ExtractAssociatedIcon(mainModuleFileName);
}
catch {
// Probably no access
return null;
}
}
}