Question

create table events (
fk_user integer,
event varchar(40),
time integer
);


Insert into events (fk_user, event, time)
VALUES
('1', 'view', '1'),
('1', 'view', '3'),
('1', 'view', '4'),
('1', 'lead', '5'),
('1', 'view', '6'),
('1', 'view', '7'),
('1', 'lead', '9'),
('2', 'view', '1'),
('2', 'lead', '2'),
('2', 'lead', '3'),
('2', 'view', '6'),
('2', 'view', '7'),
('2', 'view', '8'),
('5', 'view', '1'),
('5', 'view', '2'),
('2', 'view', '4'),
('2', 'lead', '5'),
('2', 'view', '9');

我想要找到的是：有3个观点＆＃39;在“领先”之前从顶部发生。我想取平均时间＆＃39;前三次发生。是否可以使用窗口功能？
预期输出应为：（1 + 3 + 4）/ 3 = 2.666（如果取整数则为3）

Answer 1

您可以使用min窗口函数和case语句查找每first_lead_time fkuser，然后使用派生表获取平均值在views

之前的first_lead_time行

select fkuser, avg(time) from (
    select * , 
        min (case when event = 'lead' then time end) over (partition by fkuser) as first_lead_time
    from events
) t where time < first_lead_time
and event = 'view'
group by fkuser

另一种方式

select e.fk_user, avg(e.time)
from events e
join (
    select min(time) first_lead_time, fkuser
    from events
    where event = 'lead'
    group by fkuser
) t on t.fkuser = e.fkuser
where e.time < t.first_lead_time
group by e.fkuser

查找首次潜在客户事件发生前的平均观看次数

1 个答案: