Question

我有一个函数，我想测试它是否会抛出异常：

 @Override
    public WorkOrderTask updateWorkOrderTaskWithOutcome(String taskId, String outcome, WorkOrderTask workOrderTask) {
        Map<String, Object> variables = new HashMap<>();

        if (!outcome.equals(TaskOutcomes.CANCEL.getValue())) {
            WorkOrderType workOrder = workOrderTask.getWorkOrderPayload().getWorkOrder();
            workOrder = workflowDataService.updateWorkOrder(workOrder);
            workOrderTask.getWorkOrderPayload().setWorkOrder(workOrder);

            variables = getProcessVariables(workOrder);
        }

        try {
            workflowTaskService.completeTask(taskId, outcome, variables);
            logger.debug("Updated Task ID: {} with outcome {}", taskId, outcome);
        } catch (WorkflowException e) {
            logger.error("Updating Work Order Task ID: {} with outcome {} FAILED", taskId, outcome, e);
        }

        return workOrderTask;
    }

我写的测试是这样的：

@Test(expected=WorkflowException.class)
public void testUpdateWorkOrderTaskForWorkflowException() throws Exception {
    WorkOrderTask workOrderTask = GrcWorkflowTestUtil.generateWorkOrderTask();
    WorkOrderType workOrder = workOrderTask.getWorkOrderPayload().getWorkOrder();

    doReturn(workOrder).when(workflowDataService).updateWorkOrder(workOrder);//some mock stubs to avoid calling actual service
    doThrow(new WorkflowException("test workflow exception")).when(workflowTaskService).completeTask(any(), any(), any());//forcing the exception to be thrown

    WorkOrderTask workOrderTaskRet = workOrderService.updateWorkOrderTaskWithOutcome(TestEnvironmentUtil.TASK_ID,
            TaskOutcomes.SUBMIT.getValue(), workOrderTask);

}

现在，当我运行测试时，我得到＆gt; AssertionError：例外异常：workflowException，即使我可以看到（调试）抛出了workflowException。

我确实读过这个类似的问题： Testing for Exceptions using JUnit. Test fails even if the Exception is caught

但答案是说我必须跳过try catch块，这是我不想做的事情。

此外，测试的全部要点是确保异常被捕获，我知道这似乎是我测试实现而不是API，但我不想触发实际异常，因为那样调用实际服务的保证

Answer 1

您想确保代码捕获WorkflowException吗？但你已经在这里了：

    doThrow(new WorkflowException("test workflow exception"))
    .when(workflowTaskService).completeTask(any(), any(), any());

如果测试执行没有引发异常，则意味着捕获了此模拟操作中的上升异常因此，不应指定@Test(expected=WorkflowException.class)。

如果您想确保执行了模拟方法，您仍然可以验证是否已调用workflowTaskService.completeTask()。如果它被调用，则意味着抛出了异常。

JUnit＆＃39; AssertionError＆＃39;即使抛出异常，也会出现预期的异常

1 个答案: