所以这就是我想要做的事情。我在多维数组中构建了一个位置和日期列表。我想根据日期和位置显示输出中接下来的3个即将到来的日期。此外，我需要在任何给定时刻仅显示每个位置的一个日期，所以基本上是距离位置1,2和3的最近日期，依此类推，并且每当其中一个通过时，我想用下一个最接近的日期替换它。我可能需要稍后添加更多位置，但我仍需要在输出中显示前3个即将到来的日期。我应该以不同的方式构建我的数组吗？
任何帮助将不胜感激 感谢
$event_dates = array(
'location-1' => array(
'date1' => array(
'start' => date('m-d-Y',strtotime('2017-7-30')),
'end' => date('m-d-Y',strtotime('2017-8-3')),
),
'date2' => array(
'start' => date('m-d-Y',strtotime('2018-2-18')),
'end' => date('m-d-Y',strtotime('2018-2-23')),
),
'date3' => array(
'start' => date('m-d-Y',strtotime('2018-7-29')),
'end' => date('m-d-Y',strtotime('2018-8-2')),
),
'date4' => array(
'start' => date('m-d-Y',strtotime('2019-1-27')),
'end' => date('m-d-Y',strtotime('2019-1-31')),
),
'date5' => array(
'start' => date('m-d-Y',strtotime('2019-7-28')),
'end' => date('m-d-Y',strtotime('2019-8-12')),
),
'date6' => array(
'start' => date('m-d-Y',strtotime('2020-1-16')),
'end' => date('m-d-Y',strtotime('2020-1-22')),
)
),
'location-2' => array(
'date1' => array(
'start' => date('m-d-Y',strtotime('2017-7-30')),
'end' => date('m-d-Y',strtotime('2017-8-13')),
),
'date2' => array(
'start' => date('m-d-Y',strtotime('2018-1-8')),
'end' => date('m-d-Y',strtotime('2018-2-11')),
),
'date3' => array(
'start' => date('m-d-Y',strtotime('2018-7-23')),
'end' => date('m-d-Y',strtotime('2018-8-12')),
),
'date4' => array(
'start' => date('m-d-Y',strtotime('2019-1-17')),
'end' => date('m-d-Y',strtotime('2019-1-23')),
),
'date5' => array(
'start' => date('m-d-Y',strtotime('2020-6-16')),
'end' => date('m-d-Y',strtotime('2020-6-22')),
)
),
'location-3' => array(
'date1' => array(
'start' => date('m-d-Y',strtotime('2017-5-12')),
'end' => date('m-d-Y',strtotime('2017-5-19')),
),
'date2' => array(
'start' => date('m-d-Y',strtotime('2018-9-22')),
'end' => date('m-d-Y',strtotime('2018-9-28')),
),
'date3' => array(
'start' => date('m-d-Y',strtotime('2018-3-12')),
'end' => date('m-d-Y',strtotime('2018-3-20')),
),
'date4' => array(
'start' => date('m-d-Y',strtotime('2019-12-9')),
'end' => date('m-d-Y',strtotime('2019-12-15')),
),
'date5' => array(
'start' => date('m-d-Y',strtotime('2020-11-16')),
'end' => date('m-d-Y',strtotime('2020-11-20')),
)
));
答案 0 :(得分：0)
它DateTime来救援！
代码（Demo）：
$TZ=new DateTimeZone('UTC'); // make some sort of declaration on timezone
$today=new DateTime('NOW',$TZ);
$today->setTime(0,0,0);
foreach($event_dates as $locname=>$datearray){
foreach($datearray as $eventname=>$eventarray){ // I recommend changing 'date{n}' to an actual eventname in the array
$end=DateTime::createFromFormat('m-d-Y',$eventarray['end'],$TZ)->setTime(0,0,0);
if($today<=$end){
echo "$locname's $eventname";
$start=DateTime::createFromFormat('m-d-Y',$eventarray['start'],$TZ)->setTime(0,0,0);
$days=abs($today->diff($start)->days);
if($today==$start){
echo " begins today!";
}elseif($today==$end){
echo " concludes today!";
}elseif($today<$start){
echo " starts in $days day",($days!=1?"s":"");
}else{
echo " is in progress for $days day",($days!=1?"s":"");
}
echo "\n";
break;
}
}
}
输出：
location-1's date1 starts in 114 days
location-2's date1 starts in 114 days
location-3's date1 starts in 35 days
为了尝试提供最强大的代码，我选择将我的方法转换为一个功能，允许指定要显示的事件日期数。另外，我发现location-3有一个日期不按顺序，所以我已经包含了一个sort（）来纠正这个。
代码：（Demo）
// for this sample array, $count=6 is the same as $count=-1
function currentAndUpcomingEvents($array,$location,$count=-1){ // default to -1 which will show all
$result=[];
$x=0;
$TZ=new DateTimeZone('UTC'); // make some sort of declaration on timezone
$today=new DateTime('NOW',$TZ);
$today->setTime(0,0,0);
// test a specific date: $today=DateTime::createFromFormat('m-d-Y','08-13-2017',$TZ)->setTime(0,0,0);
foreach($array[$location] as $eventname=>$daterange){
if($x==$count){break;}
$end=DateTime::createFromFormat('m-d-Y',$daterange['end'],$TZ)->setTime(0,0,0);
if($today<=$end){
$start=DateTime::createFromFormat('m-d-Y',$daterange['start'],$TZ)->setTime(0,0,0);
$days=abs($today->diff($start)->days);
$result[$days]="$location's $eventname"; // using $days as keys will allow sorting
if($today==$start){
$result[$days].=" begins today!";
}elseif($today==$end){
$result[$days].=" concludes today!";
}elseif($today<$start){
$result[$days].=" starts in $days day".($days!=1?"s":"");
}else{
$result[$days].=" is in progress for $days day".($days!=1?"s":"");
}
}
++$x;
}
ksort($result); // location-3's date3 was originally out of order
return $result;
}
foreach(array_keys($event_dates) as $location){
echo implode("\n",currentAndUpcomingEvents($event_dates,$location,6)); // whole array, level1 key, events per location count
echo "\n\n";
}
输出：
location-1's date1 starts in 114 days
location-1's date2 starts in 317 days
location-1's date3 starts in 478 days
location-1's date4 starts in 660 days
location-1's date5 starts in 842 days
location-1's date6 starts in 1014 days
location-2's date1 starts in 114 days
location-2's date2 starts in 276 days
location-2's date3 starts in 472 days
location-2's date4 starts in 650 days
location-2's date5 starts in 1166 days
location-3's date1 starts in 35 days
location-3's date3 starts in 339 days
location-3's date2 starts in 533 days
location-3's date4 starts in 976 days
location-3's date5 starts in 1319 days