Question

我有什么：

"A" HABTM "C" HABTM "A" through join table "B"
"A" hasMany "B" belongsTo "A"
"C" is ordered by a "B" field

我想要的是什么：

// result:
[0] => array( 
    A => array( /* single model's fields I still need*/ ),
    C => array(
        [0] => array( C.field1, C.field2, ... /* Model C fields*/ ), 
        [1] => array( C.field1, C.field2, ... )
    )
)

我尝试了什么：

// this gives me data I don't need:
A->find('all', array( 'conditions' => array( 'id' => $id ) ) )
// result:
[0] => array( 
    A => array( /* single model's fields I need*/ ),
    B => array( /* I DON'T NEED */
        [0] => array( ... )
        [1] => array( /* ... etc, tons records I don't need */ )
    ),
    C => array(
        [0] => array( C.field1, C.field2, ... /* I need these fields*/ 
            [B] => array( /* I DON'T NEED */ )
        ),
        [1] => array( C.field1, C.field2, ...  )
            [B] => array( /* ... etc, each has a model B I don't need ... */)
        )
    )
)

使用Containable，我可以减少相当多的查询，但仍有相关的模型：

// this is a little better
A->find('all', array( 
    'conditions' => array( 'id' => $id ),
    'contain' => array( 'C' )
))
// result:
[0] => array( 
    A => array( /* single model's fields I still need*/ ),
    C => array(
        [0] => array( C.field1, C.field2, ... /* I still need Model C fields*/ 
            [B] => array( /* I still DON'T need this Model's fields */ )
        ),
        [1] => array( C.field1, C.field2, ... 
            [B] => array( /* ... still has unneeded model B */)
        )
    )
)

NB1 ：我已阅读本书中的this，this和this，以及this和{{3 }}

NB2 ：我也试过

C->recursive = -1 // no effect

C->unbindModel(array('hasAndBelongsToMany'=>A)) // no effect

A->find('all', array(                    // not what I want, but it's still 
    'conditions' => array('id' => $id),  // odd that this doesn't filter C's 
    'contain' => array('A.B')));         // fields out. same as second result

A->find('all', array(                    // also not what I want, but it's 
    'conditions' => array('id' => $id),  // weird that this doesn't filter B's 
    'contain' => array('A.B.field')));   // fields at all;

Answer 1

ContainableBehavior将自动返回映射结果所需的字段。

从您已阅读的page引用：

$this->Post->find('all', array('contain' => 'Comment.author'));

... // data returned:

[Comment] => Array
    (
        [0] => Array
            (
                [author] => Daniel
                [post_id] => 1
            )
...

如您所见，Comment数组仅包含作者字段（加号 CakePHP需要的post_id 映射结果）。

对于HABTM关系，将返回具有关联外键的连接模型，因为Containable需要a_id和c_id字段。我的建议是忽略它并采取你需要的值。如果您愿意，您可以查看joins，因为Containable有时会多次查询数据库。但是，关联模型的数据不会像包含的那样很好地返回。

Containable不会使用HABTM＆amp; amp;过滤二级模型有很多

1 个答案: