Question

我正在处理一个我传递JSON请求的服务，我需要将它转换为XML，然后将它与一些XML模式进行比较，然后对它做一些事情。

我的问题在于属性。例如，我的JSON请求是：

{
"BookingSearch_IN": {
"MsgHeader": {      
  "MessageID": "ABC010101",
  "ContextRecord": {
    "ContextInfo": {
      "ItineraryDetails": {
        "ItinerarySeqNmbr": "1",
        "StartDate": "2017-04-01",
        "EndDate": "2017-04-14",            
        "LocationStart": {
          "LocationContext": "AIRPORT",
          "LocationCode": "MIA"
        },
        "LocationEnd": {
          "LocationContext": "AIRPORT",
          "LocationCode": "MIA"
        }
      },
      "ExtraInfoList": {
        "ExtraInfo": {
          "Category": "CRUISE",
          "Item": {
            "Code": "SHIP_CODE",
            "Value": "MAGIC"
          }
        }
      },
      "_ResType": "Vacation"
    }
  }
},
"_xmlns:xsi": "http://www.w3.org/2001/XMLSchema-instance",
"_xmlns:cs": "http://MyCompany.com",
"_version": "6.66",
"__prefix": "cs"
  }
}

我正在使用：XmlDocument doc = JsonConvert.DeserializeXmlNode(jsonObject);将其转换为XML。 xml结果是：

<BookingSearch_IN>
<MsgHeader>
    <MessageID>ABC010101</MessageID>
        <ContextRecord>
            <ContextInfo>
                <ItineraryDetails>
                    <ItinerarySeqNmbr>1</ItinerarySeqNmbr>
                    <StartDate>2017-04-01</StartDate>
                    <EndDate>2017-04-14</EndDate>                       
                    <LocationStart>
                        <LocationContext>AIRPORT</LocationContext>
                        <LocationCode>MIA</LocationCode>
                    </LocationStart>
                    <LocationEnd>
                        <LocationContext>AIRPORT</LocationContext>
                        <LocationCode>MIA</LocationCode>
                    </LocationEnd>
                </ItineraryDetails>
                <ExtraInfoList>
                    <ExtraInfo>
                    <Category>CRUISE</Category>
                    <Item>
                        <Code>SHIP_CODE</Code>
                        <Value>MAGIC</Value>
                    </Item>
                    </ExtraInfo>
                </ExtraInfoList>
                <_ResType>Vacation</_ResType>
            </ContextInfo>
        </ContextRecord>
</MsgHeader>
<xsi>http://www.w3.org/2001/XMLSchema-instance</xsi><cs>http://MyCompany.com</cs><_version>6.66</_version><__prefix>cs</__prefix>
</BookingSearch_IN>

结果XML具有文档末尾的根元素的属性，作为另一个元素(between </MsgHeader> and </BookingSearch_IN>)。我的问题是，针对其他客户的XML验证此XML的服务会检查根元素中的这些属性。以下是代码期望XML的方式：

    <?xml version="1.0" encoding="UTF-8"?>
<cs:BookingSearch_IN xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:cs="http://MyCompany.com" version="6.66">
    <MsgHeader> 
        <MessageID>ABC010101</MessageID>
        <ContextRecord>
            <ContextInfo ResType="Vacation">
                <ItineraryDetails>
                    <ItinerarySeqNmbr>1</ItinerarySeqNmbr>
                    <StartDate>2017-04-01</StartDate>
                    <EndDate>2017-04-14</EndDate>                       
                    <LocationStart>
                        <LocationContext>AIRPORT</LocationContext>
                        <LocationCode>MIA</LocationCode>
                    </LocationStart>
                    <LocationEnd>
                        <LocationContext>AIRPORT</LocationContext>
                        <LocationCode>MIA</LocationCode>
                    </LocationEnd>
                </ItineraryDetails>
                <ExtraInfoList>
                    <ExtraInfo>
                        <Category>CRUISE</Category>
                        <Item>
                            <Code>SHIP_CODE</Code>
                            <Value>MAGIC</Value>
                        </Item>     
                    </ExtraInfo>
                </ExtraInfoList>
            </ContextInfo>          
        </ContextRecord>
    </MsgHeader>        
</cs:BookingSearch_IN>

代码失败，因为它期望根元素为<cs:BookingSearch_IN xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:cs="http://MyCompany.com" version="5.22">

....有关如何处理这种情况的任何建议？或者如何将这些属性放回到它们在根元素中的位置？

Answer 1

NewtonSoft期望属性以@为前缀，而不是_或__，并且期望前缀只能被添加到名称中。例如，如果你可以让你的JSON看起来像这样：

{
    "cs:BookingSearch_IN": {
        "@xmlns:xsi": "http://www.w3.org/2001/XMLSchema-instance",
        "@xmlns:cs": "http://MyCompany.com",
        "@version": "6.66",
        "MsgHeader": {
            "MessageID": "ABC010101",
            "ContextRecord": {
                "ContextInfo": {
                    "@ResType": "Vacation",
                    "ItineraryDetails": {
                        "ItinerarySeqNmbr": "1",
                        "StartDate": "2017-04-01",
                        "EndDate": "2017-04-14",
                        "LocationStart": {
                            "LocationContext": "AIRPORT",
                            "LocationCode": "MIA"
                        },
                        "LocationEnd": {
                            "LocationContext": "AIRPORT",
                            "LocationCode": "MIA"
                        }
                    },
                    "ExtraInfoList": {
                        "ExtraInfo": {
                            "Category": "CRUISE",
                            "Item": {
                                "Code": "SHIP_CODE",
                                "Value": "MAGIC"
                            }
                        }
                    }
                }
            }
        }
    }
}

它将正常工作（请注意，您必须将这些XMLNS移到顶部 - 如果它们位于底部，则会因某种原因丢弃前缀）。

如果不可能，您必须使用不同的序列化程序或编写一些自定义逻辑来预处理/后处理您的JSON或XML。

在C＃中将JSON转换为XML时发出处理属性

1 个答案: