Question

我已根据list而不是time的属性String对date对象进行了排序。

排序前的样本输出：

07:05:10 AM
07:05:01 AM
07:04:49 AM
07:04:44 AM 
06:53:58 AM
06:53:47 AM
01:03:21 AM
12:03:21 AM

并在调用instrudtion之后：

self.myList = self.myList.sorted { $0.mytime < $1.mytime }

看起来像这样：

01:03:21 AM
06:53:47 AM
06:53:58 AM
07:04:44 AM 
07:04:49 AM
07:05:01 AM
07:05:10 AM
12:03:21 AM

我是否可以将12:03:21 AM替换为00:03:21 AM仅在AM和12开头时？

或者有不同的方法可以做到这一点？

提前致谢！

Answer 1

我认为这就是你要找的东西。总是以这种方式比较日期！

override func viewDidLoad() {
    super.viewDidLoad()
    var arrayOfDates = ["07:05:10 AM",
                        "07:05:01 AM",
                        "07:04:49 AM",
                        "07:04:44 AM",
                        "06:53:58 AM",
                        "06:53:47 AM",
                        "01:03:21 AM",
                        "12:03:21 AM"]

    // This will throw an error if any of your dates are 
    // misformatted, so handle that appropriately.                  
    arrayOfDates.sort() { $0.toDate()!.compare($1.toDate()!) == ComparisonResult.orderedDescending }
    print("Descending: \(arrayOfDates)")

    arrayOfDates.sort() { $0.toDate()!.compare($1.toDate()!) == ComparisonResult.orderedAscending }
    print("Ascending: \(arrayOfDates)")
}

extension String {
    func toDate() -> Date? {
    let formatter = DateFormatter()
    formatter.dateFormat = "hh:mm:ss a"
    if let date = formatter.date(from: self) {
        return date
    } else {
        return nil
    }
}

//If you need a string version of the date you can use this as well
extension Date {
    func toString() -> String {
        let formatter = DateFormatter()
        formatter.dateFormat = "hh:mm:ss a"
        return formatter.string(from: self)
    }
}

替换字符串列表中的字符

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