Question

实际上，我不知道该问题的标题应该是什么。

我有两个模式定义如下的表：

**Table 1 (organization_master)**:
CREATE TABLE `organization_master` (  `organization_id` int(11) NOT NULL,  `parent_organization_id` int(11) DEFAULT NULL,  `organization_name` varchar(150) NOT NULL,  `c_user_id` int(11) DEFAULT NULL) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
INSERT INTO `organization_master` (`organization_id`, `parent_organization_id`, `organization_name`, `c_user_id`) VALUES
(119, NULL, 'Patel-Apps', 220),
(183, 119, 'Patel-Apps sub 1', 220),
(184, 119, 'Patel-Apps sub 2', 220),
(250, 247, 'Patel-Apps2', 222);
ALTER TABLE `organization_master`  ADD PRIMARY KEY (`organization_id`),  ADD KEY `organization_name` (`organization_name`),  ADD KEY `c_user_id` (`c_user_id`);
ALTER TABLE `organization_master`  MODIFY `organization_id` int(11) NOT NULL AUTO_INCREMENT;


**Table 2 (organization_assigned_user)** :
CREATE TABLE `organization_assigned_user` (  `organization_assigned_user_id` int(11) NOT NULL,  `organization_id` int(11) DEFAULT NULL,  `user_id` int(11) DEFAULT NULL) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `organization_assigned_user` (`organization_assigned_user_id`, `organization_id`, `user_id`) VALUES (29, 250, 219),(30, 250, 220);
ALTER TABLE `organization_assigned_user`  ADD PRIMARY KEY (`organization_assigned_user_id`),  ADD KEY `user_id` (`user_id`),  ADD KEY `organization_id` (`organization_id`);
ALTER TABLE `organization_assigned_user`  MODIFY `organization_assigned_user_id` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=31;

当我在查询下运行时，它给我输出如下：

SELECT om.organization_id, om.parent_organization_id, om.organization_name FROM `organization_master` AS om LEFT JOIN organization_assigned_user AS oau ON om.organization_id = oau.organization_id WHERE om.c_user_id =220 OR oau.user_id =220 GROUP BY om.organization_id 

organization_id parent_organization_id  organization_name
119             NULL                    Patel-Apps
183             119                     Patel-Apps sub 1
184             119                     Patel-Apps sub 2
250             247                     Patel-Apps2

现在，我的问题是我不希望在organization_id列中存在parent_organization_id的行。即，parent_organization_id存在于organization_id中。所以我的出局应该如下所示。

organization_id parent_organization_id  organization_name
119             NULL                    Patel-Apps
250             247                     Patel-Apps2

Answer 1

你可以尝试这个

<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>


<div class="form-group form-margin">
    <label class="col-lg-4 control-label">Username:</label>
    <div class="col-lg-7">
         <input type="text" name='username' class='form-control error' id='username'>
    </div>
</div>
<div class="form-group">
    <label class="col-lg-4 control-label">Password:</label>
    <div class="col-lg-7">
        <input type="text" name='password' class='form-control error' id='password'>
    </div>
</div>
<div class="row">
    <div class="col-lg-10 col-lg-offset-1">
       <button id="btnSubmit" class="'btn btn-primary form-control">Sign In</button>
    </div>
</div>

mysql：如果父ID在主键columan中匹配，则删除行

1 个答案: