Question

在我的phpmyadmin数据库中，我有一个名为rooms的表，有2列。第1列名为room name并包含值：bookstore,foodcourt, etc.第2列名为images并包含图像的路径：/image/bookstore.jpg, /image/foodcourt.jpg, etc.

form.php 包含提交给bookstore,foodcourt,etc的用户输入，例如image.php

<form name="form" method="POST" action="image.php">
    <fieldset>
        <p>Where are you trying to go? </p>
        <input type="text" name="mapinput" id="mapinput">
<br />
<br />
<input type="submit" name="submit" value="Submit">
</fieldset>
</form>

image.php 应该将用户输入与数据库图像路径匹配，并根据用户输入回显图像。

<?php
$conn=mysqli_connect("localhost","xxx","xxx","Capstone");
if (mysqli_connect_errno())
{
echo "Connect failed: " . mysqli_connect_error();
exit();
}

if (isset($_POST['mapinput'])) //mapinput is the user input from the form
{
      $map = $_POST['mapinput']; //user input is assigned variable $map
      $sql = "SELECT images FROM rooms WHERE room name=$map"; //selecting column images from table rooms where room name = user input ($map)
      $result = mysqli_query($conn,$sql);

while($row = mysql_fetch_array($result))
  {
    echo  "<img src = 'images" . $row['images'] . "' />"  //images is the column name that holds the image path
  }

}

mysqli_close($conn);

?>

执行时，它不会从关联的数据库图像路径发布任何图像。欢迎任何帮助，谢谢。

Answer 1

这似乎是一个路径问题。最好的想法是打开一个萤火虫。尝试检查破损的图像。您将能够了解路径出了什么问题。一旦遇到问题，请在 $ row ['images'] 之前添加正确的网址。

通过图像路径从phpmyadmin获取图像并在页面上查看

1 个答案: