Question

我是测试的新手。所以，我有一个学习任务。

该程序计算二次方程。

我如何检查，例如，c！= 0和D＆gt; 0使用JUnit？

我想以正确的方式做到这一点。

我试图从JUnit调用input（），但测试变得无穷无尽。

public class Main {
public static Scanner input;
public static double a, b, c;
public static double d;
public static double x1, x2;

public static void main(String args []) {
    input();
}

public static void input() {
    System.out.println("ax^2 + bx + c = 0");
    input = new Scanner(System.in);
    try {
        System.out.print("a -> ");
        a = input.nextFloat();
        System.out.print("b -> ");
        b = input.nextFloat();
        System.out.print("c -> ");
        c = input.nextFloat();
    } catch (InputMismatchException e) {
        System.out.println("Input number!\n");
        input();
    }

    if(a == 0 || b == 0 || c == 0) {
        System.out.println("Not right\n");
        input();
        return;
    }

    calculate();
}

public static void calculate() {
    d = (b * b) - (4 * a * c);
    System.out.println("D = " + d);

    if(d < 0) {
        System.out.print("No answer");
    } else if(d == 0) {
        x1 = (-b) / (2 * a);
        System.out.println ("x = " + x1);
    } else {
        x1 = (-b + Math.sqrt(d)) / (2 * a);
        x2 = (-b - Math.sqrt(d)) / (2 * a);
        System.out.println("x1 =  " + x1);
        System.out.println("x2 = " + x2);
    }
}

}

Answer 1

您的程序目前的形式无法测试。这是另一种选择：

public class Parabola {
  // These are required in the constructor. Omitted for brevity
  private final double a;
  private final double b;
  private final double c;
  // Public API. Test this
  public double x1() { /*...*/ }
  public double x2() { /*...*/ }
}

现在编写测试很简单：

@Test public void test1() {
  Parabola target = new Parabola(1, 2, 3);
  assertEquals(target.x1(), 44.23);
  assertEquals(target.x2(), 17.23);
}

@Test public void test2() {
  Parabola target = new Parabola(1, 0, 0);
  assertEquals(target.x1(), -1);
  assertEquals(target.x2(), 13.43);
}

最后这就是main()的样子：

public void main(String... args) throws Exception {
  Scanner console = ...;
  System.out.println("Type a:");
  Double a = Double.parseDouble(console.nextLine());
  // Same for b and c
  Parabola p = new Parabola(a, b, c);
  System.out.println("X axis intersected in "  + p.x1() + " and " + p.x2());
}

_{Bonus：在单元测试中比较double时，您可能希望使用接受threshold参数的this version of assertEquals()，因为浮点运算的工作方式和/或二进制数的十进制表示}

在JUnit中测试数据

1 个答案: