Question

基本上我设置了我的程序，以便它接收名称，然后将它们分开，直到它达到1到9之间的数字，所以如果数字是35，它将分裂为5和3，这给出了8.我的问题与我的程序是，如果我要求只输入一个名称，它会给出一个错误，但2和更高的名称有效吗？它也必须工作，如果数字上升到325，因为它需要3 + 2 + 5然后之后它将是10然后再分裂给1 + 0然后是1.最后我也希望能够有一个含义=“”而且从1到9的totalValue会有一个含义，就像这个值意味着你的强者或思想家或好的演讲者或其他什么。主要问题是名称列表是否有一种方法可以绕过num_names中只有一个数字的限制，这样我可以一直到无限数字？我该怎么办？我相信这段代码可能会有所帮助，但我不确定。 list_names = list（names）

def name_value(name):
    return sum((ord(chr) - 65) % 9 + 1 for chr in name)

totalValue = 0
for list_name in names:
    totalValue += name_value(list_name)

我不知道在哪里放这个

import sys


print("Please enter each name when asked without any spaces.") #The program will post this
print("Please enter each of your names individually also.")    #Program will again post this




names = [] #This is the value of names which will be changed depending on the input
currentnum = 0 #Currentnum value is 0

while True:
    try:
    num_names = int(input("Enter number of names: "))
    break
except ValueError:
        print("That's not a number!")



for i in range(num_names):
name = input("Enter name " + str(i) + " :")
name = name.upper()
while True:
    if name.isalpha():
        break
    else:
           name = input("Enter name number " + str(i) + " again:")
names.append(name)


num1 = ["A", "J", "S"]
num2 = ["B", "K", "T"]
num3 = ["C", "L", "U"]
num4 = ["D", "M", "V"]    #This is a dictionary giving all the upper case letters a value of num1, num2 etc
num5 = ["E", "N", "W"]
num6 = ["F", "O", "X"]
num7 = ["G", "P", "Y"]
num8 = ["H", "Q", "Z"]
num9 = ["I", "R"]

totalValue = 0

list_names = list(names)

first_name = list_names[0]
second_name = list_names[1]
#third_name = list_names[2]

print(first_name)
print(second_name)
#print(third_name)
print(list_names)




for chr in first_name:      #if, elif and else code
        if (chr in num1):
                totalValue += 1
        elif (chr in num2):
                totalValue += 2
        elif (chr in num3):
                totalValue += 3
        elif (chr in num4): 
                totalValue += 4       #This gives TotalValue(the number answer) depending on the letter
        elif (chr in num5): 
                totalValue += 5
        elif (chr in num6): 
                totalValue += 6
        elif (chr in num7):
                totalValue += 7
        elif (chr in num8):
                totalValue += 8
        elif (chr in num9):
                totalValue += 9
    else:
            print("program failure")


for chr in second_name:      #if, elif and else code
    if (chr in num1):
            totalValue += 1
    elif (chr in num2):
            totalValue += 2
    elif (chr in num3):
            totalValue += 3
    elif (chr in num4): 
            totalValue += 4       #This gives TotalValue(the number answer) depending on the letter
    elif (chr in num5): 
            totalValue += 5
    elif (chr in num6): 
            totalValue += 6
    elif (chr in num7):
            totalValue += 7
    elif (chr in num8):
            totalValue += 8
    elif (chr in num9):
            totalValue += 9
    else:
            print("You have entered invalid inputs for names. Program will Now end.")




values = []
totalCount = 0
for x in values:                           #This will activate or iterate the loop for the value
    totalCount = totalCount + x     #This will add all the values together and to give a totalcount


while len(str(totalValue)) != 1:        #The code will split the 2 digit number until the addition equals to 1 digit 
        num = 0 
        for x in str(totalValue):       #This is the value x in the string     totalcount
            num = num + int(x)       #This means that the number being output will have the int of the value x
            totalValue = str(num)    #The totalCount must equal to the string of num

#[int(d) for d in str(totalValue)]    

print(totalValue)

Answer 1

好吧，我想我不是你想要的。看看：

import sys

def sumString2Digit(the_char):
    d = ord(the_char.upper()) - 65 + 1
    r = 0
    while d:
        r, d = r + d % 10, d // 10
        if d == 0 and r >= 10 :
            d = r
            r = 0
    return r

#all_names = "John Smith" #Expected output: 44
all_names = raw_input("Enter ALL names separated by spaces: ")
names  = all_names.split(' ')

res = []
for name in names:
    res.append(sum(map(lambda x: sumString2Digit(x), name)))
print ("the code for {} is {}".format(all_names, sum(res)))

示例：

$python <scriptName> $Enter ALL names separated by spaces: John Smith $the code for John Smith is 44

如何拆分数字并添加然后拆分直到1位数字

1 个答案: