Question

我通常通过给出批处理命令％~dp0来组合多个csv文件来获取当前工作目录。但是我在获取当前工作目录时遇到了＆符号（＆amp;）符号，这使得'＆amp;'后批处理文件中断了说＆amp;之后的路径不被视为内部或外部命令。

你们中的任何人都可以帮我修改我的下面的脚本来识别＆amp;并用^＆amp;替换它（因为这可以逃避＆amp;并运行批处理文件）。您的任何建议都表示赞赏;

这是我的代码：

@echo off

ECHO Set working directory
pushd %~dp0             - How to escape & in this line???

ECHO Deleting existing combined file
del combined.csv

setlocal ENABLEDELAYEDEXPANSION

REM set count to 1
set cnt=1

REM for each file that matches *.csv

for %%i in (*.csv) do (

REM if count is 1 it's the first time running

  if !cnt!==1 (

REM push the entire file complete with header into combined.csv - this will also create combined.csv

for /f "delims=" %%j in ('type "%%i"') do echo %%j >> combined.csv

REM otherwise, make sure we're not working with the combined file and
  ) else if %%i NEQ combined.csv (

REM push the file without the header into combined.csv
    for /f "skip=1 delims=" %%j in ('type "%%i"') do echo %%j >> combined.csv
  )

REM increment count by 1
  set /a cnt+=1
)

cmd \k

Answer 1

在%~dp0附近加上引号应该足够了：

...
pushd "%~dp0"
...

是的，我不明白你使用pushd的原因。您不必在代码中的任何位置popd，因此pushd似乎毫无用处。如果我正确理解ECHO Set working directory，您应该将pushd替换为CD %~dp0。

如何从批处理文件中的当前工作目录％~dp0中转义Ampersand（＆amp;）

1 个答案: