Question

我使用createQueueBrowser迭代队列的所有消息，它一旦读取就从队列中删除所有消息，我想迭代遍历所有消息而不删除队列。怎么做？

    public class Receive {
        ConnectionFactory connectionFactory = null;
        Connection connection = null;

        void receivemsg() throws JMSException {
            connectionFactory = new JmsConnectionFactory("RootManageSharedAccessKey",
                    "Gkt0Egjp/5YTrqAf9z+f2+HoRungEOh4OMSRA69js6M=",
                    "amqps://amqpqpid.servicebus.windows.net?amqp.idleTimeout=-1");

            /*
             * connectionFactory = new
             * JmsConnectionFactory("RootManageSharedAccessKey",
             * "Gkt0Egjp/5YTrqAf9z+f2+HoRungEOh4OMSRA69js6M=",
             * "amqps://amqpqpid.servicebus.windows.net?amqp.idleTimeout=-1");
             */

            connection = connectionFactory.createConnection();
            connection.start();
            System.out.println("Receiving messages...");
            Session session = connection.createSession(false, Session.CLIENT_ACKNOWLEDGE);
            Destination replyQueue = session.createQueue("ackqueue");
            //MessageConsumer consumer = session.createConsumer(replyQueue);
            TextMessage message = session.createTextMessage();
            Queue recieve = session.createQueue("requestor");

            QueueBrowser browser = session.createBrowser(recieve);

            Enumeration msgs = browser.getEnumeration();


            if (!msgs.hasMoreElements()) {
                System.out.println("No messages in queue");
            } else {

                while (msgs.hasMoreElements()) {
                    Message tempMsg = (Message) msgs.nextElement();

                    System.out.println("Message: " + tempMsg.getJMSCorrelationID());
                    if(tempMsg.getJMSCorrelationID().equalsIgnoreCase("helloworld"))
                    {

                        System.out.println("matched and acked");
                        break;
                    }
                }
            }


        }

        public static void main(String args[]) throws JMSException {

            Receive receiver = new Receive();

            receiver.receivemsg();

            System.out.println("Received Messages");
        }
    }

Answer 1

我查看了Apache Qpid的文档，没有任何方法或选项可以支持消费者在AMQP客户端内无损。 Qpid的唯一方法是为Qpid代理服务器端的qpid.ensure_nondestructive_consumers选项强制设置true，但它不适合您当前的方案Azure Service Bus Queue。

在Azure Service Bus Queue上，有一个REST API Peek-Lock Message (Non-Destructive Read)可以满足您的需求。因此，您可以参考服务总线队列官方教程的Receive messages from a queue部分，使用Azure Java SDK for Service Bus在下面的代码中设置ReceiveMode.PEEK_LOCK来执行此操作。

ReceiveMessageOptions opts = ReceiveMessageOptions.DEFAULT;
opts.setReceiveMode(ReceiveMode.PEEK_LOCK);

希望它有所帮助。

是否可以禁用jms的createQueueBrowser的自动确认？

1 个答案: