我想使用openpyxl
在python中打印特定列的所有数据(所有行)我正在以这种方式工作;
from openpyxl import load_workbook
workbook = load_workbook('----------/dataset.xlsx')
sheet = workbook.active
for i in sheet:
print(sheet.cell(row=i, column=2).value)
但它给出了
如果行< 1或列< 1: TypeError:unorderable类型:tuple()< INT()
因为我正在row=i
进行迭代。如果我使用sheet.cell(row=4, column=2).value
它会打印单元格的值。但是我如何迭代所有文档呢?
修改1
在一些研究中,发现可以使用工作表名称获取数据。 Sheet 1
文件中存在.xlsx
,但其数据未打印。这段代码有什么问题吗?
workbook = load_workbook('---------------/dataset.xlsx')
print(workbook.get_sheet_names())
worksheet =workbook.get_sheet_by_name('Sheet1')
c=2
for i in worksheet:
d = worksheet.cell(row=c, column=2)
if(d.value is None):
return
else:
print(d.value)
c=c+1
答案 0 :(得分:11)
对worksheets
中的所有workbook
进行迭代,例如:
for n, sheet in enumerate(wb.worksheets):
print('Sheet Index:[{}], Title:{}'.format(n, sheet.title))
输出:
Sheet Index:[0], Title: Sheet Sheet Index:[1], Title: Sheet1 Sheet Index:[2], Title: Sheet2
对一个工作表中的所有rows
和columns
进行迭代:
worksheet = workbook.get_sheet_by_name('Sheet')
for row_cells in worksheet.iter_rows():
for cell in row_cells:
print('%s: cell.value=%s' % (cell, cell.value) )
输出:
<Cell Sheet.A1>: cell.value=²234
<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.C1>: cell.value=C1
<Cell Sheet.D1>: cell.value=D1
<Cell Sheet.A2>: cell.value=1234
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.C2>: cell.value=C2
<Cell Sheet.D2>: cell.value=D2
对所有columns
一个 row
进行迭代,例如row==2
:
for row_cells in worksheet.iter_rows(min_row=2, max_row=2):
for cell in row_cells:
print('%s: cell.value=%s' % (cell, cell.value) )
输出:
<Cell Sheet.A2>: cell.value=1234
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.C2>: cell.value=C2
<Cell Sheet.D2>: cell.value=D2
迭代全部 rows
,仅column
2 :
for col_cells in worksheet.iter_cols(min_col=2, max_col=2):
for cell in col_cells:
print('%s: cell.value=%s' % (cell, cell.value))
输出:
<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.B3>: cell.value=9.8
<Cell Sheet.B4>: cell.value=10.1
<Cell Sheet.B5>: cell.value=7.7
使用Python测试:3.4.2 - openpyxl:2.4.1 - LibreOffice:4.3.3.2
答案 1 :(得分:1)
试试这个,
from openpyxl import load_workbook
workbook = load_workbook('----------/dataset.xlsx')
sheet = workbook.active
row_count = sheet.max_row
for i in range(row_count):
print(sheet.cell(row=i, column=2).value)
答案 2 :(得分:0)
此代码将读取工作表,就像它是csv一样,并使用第一行作为列标题在result
中填充字典列表。
from openpyxl import load_workbook
result = []
wb = load_workbook(filename=file_name)
sheet = wb.active
col_count = sheet.max_column
column_names = {}
for c in range(1, col_count):
heading = sheet.cell(row=1, column=c).value
if not heading:
col_count = c
break
column_names[c] = heading
for r, row_cells in enumerate(sheet.iter_rows(2), 2):
row = {}
for c in range(1, col_count):
value = sheet.cell(row=r, column=c).value
if type(value) == datetime:
value = value.strftime('%Y-%m-%d')
row[column_names[c]] = value
result.append(row)