我有这个.csv文件......
id,first_name,last_name,email,date,opt-in
1,Jimmy,Reyes,jreyes0@macromedia.com,12/29/2016,FALSE
2,Doris,Wood,dwood1@1und1.de,04/22/2016,
3,Steven,Miller,smiller2@go.com,07/31/2016,FALSE
4,Earl,Parker,eparker3@ucoz.com,01-08-17,FALSE
5,Barbara,Cruz,bcruz4@zdnet.com,12/30/2016,FALSE
我想阅读上面显示的csv文件,转换数据,最后将数据写入另一个文本文件中,这应该是这样的....
1,<tab>"first_name"="Jimmy","last_name"="Reyes","email"="jreyes0@macromedia.com","date"="12/29/2016","opt-in"="FALSE"
2,<tab>"first_name"="Doris","last_name"="Wood","email"="dwood1@1und1.de","date"="04/22/2016,,"opt-in"="0"
此外,如果选择加入值为空,则应打印“0”。
到目前为止,这是我的代码......
import csv
import time
# Do the reading
with open('my-scripts/mock.csv', 'r') as f1:
#next(f1, None) # skip the headers
reader = csv.reader(f1)
new_rows_list = []
for row in reader:
if row[5] == '':
new_row = [row[0],'\t',row[1], row[2], row[3], row[4], '0']
new_rows_list.append(new_row)
else:
new_row = [row[0],'\t',row[1], row[2], row[3], row[4], row[5]]
new_rows_list.append(new_row)
f1.close() # <---IMPORTANT
# Do the writing
newfilename = 'my-scripts/ftp_745198_'+str(int(time.time()))
with open(newfilename, 'w', newline='') as f2:
writer = csv.writer(f2, quoting=csv.QUOTE_NONNUMERIC)
writer.writerows(new_rows_list)
f2.close()
上面的代码生成了这个输出,这不是我想要的...... 我无法弄清楚如何在每行中打印列名,如上图所示的所需输出......!< / strong>
"id"," ","first_name","last_name","email","date","opt-in"
"1"," ","Jimmy","Reyes","jreyes0@macromedia.com","12/29/2016","FALSE"
"2"," ","Doris","Wood","dwood1@1und1.de","04/22/2016","0"
"3"," ","Steven","Miller","smiller2@go.com","07/31/2016","FALSE"
"4"," ","Earl","Parker","eparker3@ucoz.com","01-08-17","FALSE"
"5"," ","Barbara","Cruz","bcruz4@zdnet.com","12/30/2016","FALSE"
新CSV
id,first_name,last_name,email,date,opt-in,unique_code
1,Jimmy,Reyes,jreyes0@macromedia.com,12/29/2016,FALSE,ER45DH
2,Doris,Wood,dwood1@1und1.de,04/22/2016,,MU34T3
3,Steven,Miller,smiller2@go.com,07/31/2016,FALSE,G34FGH
4,Earl,Parker,eparker3@ucoz.com,01-08-17,FALSE,ASY67J
5,Barbara,Cruz,bcruz4@zdnet.com,12/30/2016,FALSE,NHG67P
新的预期输出
ER45DH<tab>"id"="1","first_name"="Jimmy","last_name"="Reyes","email"="jreyes0@macromedia.com","date"="12/29/2016","opt-in"="FALSE"
MU34T3<tab>"id"="2","first_name"="Doris","last_name"="Wood","email"="dwood1@1und1.de","date"="04/22/2016,"opt-in"="0"
我将非常感谢任何帮助/想法/指针。
由于
答案 0 :(得分:1)
您可以将标题保留在列表中,然后使用列表(如first_name等)匹配后续行中的元素(如Jimmy等)以生成您想要的输出(&#34;如first_name&#34; =&#34;麦&#34;。)
答案 1 :(得分:1)
首先,将标题保存到变量中。例如:
for i,row in enumerate(reader):
if i == 0:
header = row
else:
new_row = [row[0],'\t'] + ['%s=%s' % (header[j],row[j]) for j in range(1,6)]
....
...
其次,[row[1], row[2], row[3], row[4], row[5]]
之类的代码可以简化为[row [i] for i in range(1,6)](generator)
第三,format是一个很好的工具:
print('"%s"="%s"'% (header[1],row[1]))
将输出"first_name"="Jimmy"
使用这些知识并考虑如何使其发挥作用。
答案 2 :(得分:1)
最初将标题解压缩为新列表。
然后将每个行元素的标题追加为字符串。
将其写入文件。
请尝试使用此代码,
var str = '<div>test</div><p>test</p><span class="removedata">X</span><span>test</span><span class="removedata">X</span>',
str2 = str.replace(/<span class="removedata">X<\/span>/g, '');
console.log(str2);
<强>输出:强>
import csv
with open('newfilename.csv', 'w') as f2:
with open('mycsvfile.csv', mode='r') as infile:
reader = csv.reader(infile)
for i,rows in enumerate(reader):
if i == 0:
header = rows
else:
if rows[5] == '':
rows[5] = 0;
pat = rows[0]+'\t'+'''"%s=%%s",'''*(len(header)-1)+'\n'
print pat
f2.write(pat % tuple(header[1:]) % tuple(rows[1:]))
f2.close()
如有任何疑问,请与我们联系。