checkbox
ng-form
HTML5 form
$state
$pristine
$dirty
ignoreDirty
ng-form
HTML5 form
<form name="mainForm" class="col-xs-10 form-validation" novalidate>
<ng-form name="innerForm">
<div>
<span>check my
<span ng-if="vm.utils.mode!=='readonly'">
<input type="checkbox"
ng-model="vm.utils.amalotSecond"
class="secondYearCheckBox">
</span>
</span>
</div>
</ng-form>
<form>
{@}} True\r\n
False\r\n
True
False
r'^[.]+|[\r]+|[\n]+(True\r\n)$'
或\r
)。
我尝试使用import re
sample_response = 'var0 = 0x00000001\r\nTrue\r\n'
re_true = re.compile(r'^[.]+|[\r]+|[\n]+(True\r\n)$')
print re_true.search(sample_response).group(0) # Will print out '\r'
指令 - Angular 1.2: Is it possible to exclude an input on form dirty checking?
和其他一些解决方案,import re
sample_response = 'var0 = 0x00000001\r\nTrue\r\n'
re_true = re.compile(r'(?<=(True\r\n))')
print re_true.search(sample_response).group(0) # Will print out ''
print re_true.search(sample_response).group(1) # Will print out 'True\r\n'
for file in `git diff [start-sha] [end-sha] --name-only`;
do echo -n "$file "; git log --pretty=short [start-sha] [end-sha] -- $file | /bin/grep commit | cut -b8- | head -n 1;
done
内的static class Global
{
private static List<GridRows> _globalVar = new List<GridRows>();
public static void ResetGridData()
{
_globalVar = new List<GridRows>();
}
public static GridRows SetRow
{
set { _globalVar.Add(value); }
}
public static List<GridRows> GetSetting { get { return _globalVar; } }
public class GridRows
{
public string Cell_1 { get; set; }
public string Cell_2 { get; set; }
public string Cell_3 { get; set; }
public string Cell_4 { get; set; }
}
}
无效,代码如下:
public partial class Form2 : Form
{
public Form2()
{
//To reset our temporary store on load
Global.ResetGridData();
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
//Send data from form 2 to form 1
Form1 b = new Form1(dataGridView1.SelectedRows[0].Cells[2].Value.ToString(),
dataGridView1.SelectedRows[0].Cells[3].Value.ToString(),
dataGridView1.SelectedRows[0].Cells[4].Value.ToString(),
dataGridView1.SelectedRows[0].Cells[5].Value.ToString());
b.ShowDialog();
}
}
答案 0 :(得分:5)
您提供的ignoreDirty
指令可以像demo fiddle一样正常工作。以下代码示例取自angular-1-2-is-it-possible-to-exclude-an-input-on-form-dirty-checking。还要尽量避免使用不符合HTML的嵌套表单。 form
元素不能包含元素form
。它会导致问题和错误,例如你正面临的那个。
<div ng-controller="MyCtrl">
<form name="test">
Watching dirty: <input ng-model="name" /><br />
Ignoring dirty: <select ng-model="gender" ignore-dirty>
<option>male</option>
<option>female</option>
</select><br />
dirty: {{test.$dirty}}
</form>
</div>
var myApp = angular.module('myApp',[]);
myApp.controller('MyCtrl', function ($scope) {
$scope.name = 'Superhero';
});
myApp.directive('ignoreDirty', [function() {
return {
restrict: 'A',
require: 'ngModel',
link: function(scope, elm, attrs, ctrl) {
ctrl.$setPristine = function() {};
ctrl.$pristine = false;
}
}
}]);