Question

我有以下版本的Hibernate的Java SE应用程序：信息：HHH000412：Hibernate Core {5.2.9.Final} 信息：HCANN000001：Hibernate Commons Annotations {5.0.1.Final}

无法初始化：entityManagerF = Persistence.createEntityManagerFactory（＆＃34; mgr＆＃34;）;

导致以下异常：

WARN: GenerationTarget encountered exception accepting command : Error executing DDL via JDBC Statement
org.hibernate.tool.schema.spi.CommandAcceptanceException: Error executing DDL via JDBC Statement
    at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:67)
    at org.hibernate.tool.schema.internal.SchemaCreatorImpl.applySqlString(SchemaCreatorImpl.java:440)
    at org.hibernate.tool.schema.internal.SchemaCreatorImpl.applySqlStrings(SchemaCreatorImpl.java:424)
    at org.hibernate.tool.schema.internal.SchemaCreatorImpl.createFromMetadata(SchemaCreatorImpl.java:315)
    at org.hibernate.tool.schema.internal.SchemaCreatorImpl.performCreation(SchemaCreatorImpl.java:166)
    at org.hibernate.tool.schema.internal.SchemaCreatorImpl.doCreation(SchemaCreatorImpl.java:135)
    at org.hibernate.tool.schema.internal.SchemaCreatorImpl.doCreation(SchemaCreatorImpl.java:121)
    at org.hibernate.tool.schema.spi.SchemaManagementToolCoordinator.performDatabaseAction(SchemaManagementToolCoordinator.java:155)
    at org.hibernate.tool.schema.spi.SchemaManagementToolCoordinator.process(SchemaManagementToolCoordinator.java:72)
    at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:309)
    at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:445)
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:889)
    at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:58)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:39)
    at entities.HibernateUtil.initialize(HibernateUtil.java:64)
    at entities.HibernateUtil.getEntityManager(HibernateUtil.java:49)
    at com.company.RunS.<clinit>(RunS.java:30)
Caused by: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'type=MyISAM' at line 104
    at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:536)
    at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:513)
    at com.mysql.cj.jdbc.exceptions.SQLExceptionsMapping.translateException(SQLExceptionsMapping.java:115)
    at com.mysql.cj.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:1983)
    at com.mysql.cj.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:1936)
    at com.mysql.cj.jdbc.StatementImpl.executeInternal(StatementImpl.java:891)
    at com.mysql.cj.jdbc.StatementImpl.execute(StatementImpl.java:795)
    at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:54)
    ... 17 more

并且因此无法创建表格。谁能告诉我如何使Hibernate工作？

Answer 1

... syntax to use near 'type=MyISAM' ...就是问题所在。

这是旧语法。将type更改为engine以解决您的问题。

如果Hibernate生成错误的语法，请升级它！

为什么Hibernate无法创建表？

1 个答案: