问题
**question_id question option1 option2 option3 option4 answer**
15 AAA a1 a2 a3 a4 3
38 BBB b1 b2 b3 b 2
39 CCC c1 c2 c3 c4 4
44 DDD d1 d2 d3 d4 2
45 EEE e1 e2 e3 e4 1
start_exam.php
$query="select * from exam_question_list where exam_paper_id='$exam_paper_id'";
$result=mysqli_query($dbcon,$query);
$row = mysqli_fetch_array($result);
$que1=$row['q1'];
<form action="exam_paper_result.php?1=<?php echo $row['q1'];?>>
<?php
$sql1="SELECT question_id AS qid, question AS q, option1 AS op1, option2 AS op2, option3 AS op3, option4 AS op4 FROM question where question_id='$que1'";
$data1=mysqli_query($dbcon,$sql1);
while($datan1 = mysqli_fetch_array($data1)){
$i=0;
?>
<tr>
<tr data-label="Question"><td><span>(01) </span><?php echo $datan1['q']; ?></td></tr>
<tr data-label="Question"><td><input type="radio" name="a1" value="1"/><?php echo $datan1['op1']; ?></td></tr>
<tr data-label="Question"><td><input type="radio" name="a1" value="2"/><?php echo $datan1['op2']; ?></td></tr>
<tr data-label="Question"><td><input type="radio" name="a1" value="3"/><?php echo $datan1['op3']; ?></td></tr>
<tr data-label="Question"><td><input type="radio" name="a1" value="4"/><?php echo $datan1['op4']; ?></td></tr>
</tr>
<?php
}
?>
<input name="submit" type="submit" id="Submit" value="Submit"/>
</form>
exam_paper_result.php
if (isset ($_POST['submit'])) {
$qu1 =$_GET['1'];
$q1 = $_POST['a1'];
$score ="";
$sql1="SELECT question_id AS qid, answer AS a FROM question where question_id='$qu1'";
$result1=mysqli_query($dbcon,$sql1);
$row1=mysqli_fetch_array($result1);
if (!isset($q1)) {
echo("Error: please specify a type, new or old");
//$score = 0;
} else {
if($row1['a'] == $q1){
echo "correct";
//$score = 1;
}else{
echo "wrong";
//$score = 1;
}
}
}
?>
当我选择正确的选项然后打印'正确' 当我选择错误的选项然后打印'错误' 当我没有选择任何选项并单击提交时;有错误
“注意:未定义的索引:第38行的G:\ xampp \ htdocs \ examination_system \ src \ applicant \ exam_paper_result.php中的a1 错误:不选择任何答案“
答案 0 :(得分:0)
如果没有选中单选按钮,则可能会在此行中显示该通知:
$q1 = $_POST['a1'];
将其更改为:
$q1 = isset($_POST['a1']) ? $_POST['a1'] : NULL;
答案 1 :(得分:0)
确定变量是否已设置且不为NULL。所以你需要使用isset函数。
$q1 = null;
if(isset($_POST['a1'])){
$q1 = $_POST['a1'];
}
你也可以使用这个条件
$q1 = isset($_POST['a1']) ? $_POST['a1'] : null;
并且您需要这样的任何收音机类型,然后您不能在不检查任何收音机的情况下提交此表格
<form>
<label for="input1">Label 1:</label>
<input type="radio" name="radio" id="input1" value="1" required> <br>
<label for="input2">Label 2:</label>
<input type="radio" name="radio" id="input2" value="2"><br>
<label for="input3">Label 3:</label>
<input type="radio" name="radio" id="input3" value="3"><br>
<input type="submit" value="send">
</form>
有关详细信息,请查看此