Question

我有一个XML文件，我必须从中提取标签中的属性值。这种结构中的XML类型

<customer> 
    <customerMiddleInitial>W</customerMiddleInitial> 
<name>
      <FirstName>XXXXXXXX</FirstName>
      <LastName> YYYYYYYY</LastName>
</name>
    <customerBirth>1983-01-01</customerBirth> 
    <customerWorkPhone>020 1234567</customerWorkPhone> 
    <customerMobilePhone>0799 1234567</customerMobilePhone> 
    <previousCust>0</previousCust> 
    <timeOnFile>10</timeOnFile> 
    <customerId>CUST123</customerId>
</customer>

所以，我想提取标签之间的所有细节。预期的输出应该是所有客户的详细信息。

我如何在C＃中实现这一点？任何帮助将不胜感激。

Answer 1

XmlDocument DOC = new XmlDocument();
DOC.Load("LoadYourXMLHere.xml");
XmlNodeList ParentNode = DOC.GetElementsByTagName("customer");
foreach (XmlNode AllNodes in ParentNode)
{
 if (ParentNode == DOC.GetElementsByTagName("customerMiddleInitial"))
{
    customer.Initial = AllNodes["customerMiddleInitial"].InnerText;
}
if (ParentNode == DOC.GetElementsByTagName("name"))
{
    customer.FirstName= AllNodes["FirstName"].InnerText;
    customer.LastName= AllNodes["LastName"].InnerText;
}
if (ParentNode == DOC.GetElementsByTagName("customerBirth"))
{
    customer.Birthdate= AllNodes["customerBirth"].InnerText;
}
if (ParentNode == DOC.GetElementsByTagName("customerWorkPhone"))
{
    customer.WorkPhone= AllNodes["customerWorkPhone"].InnerText;
}
if (ParentNode == DOC.GetElementsByTagName("customerMobilePhone"))
{
    customer.MobilePhone = AllNodes["customerMobilePhone"].InnerText;
}
if (ParentNode == DOC.GetElementsByTagName("previousCust"))
{
    customer.PreviousCust= AllNodes["previousCust"].InnerText;
}
if (ParentNode == DOC.GetElementsByTagName("timeOnFile"))
{
    customer.TimeOnFile= AllNodes["timeOnFile"].InnerText;
}
if (ParentNode == DOC.GetElementsByTagName("customerId"))
{
    customer.ID= AllNodes["customerId"].InnerText;
}
}

创建Customer模型并在C＃中执行上述xml解析。

此致

Thiyagu Rajendran

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。

Answer 2

首先，您需要看到此answer

当你generated模型只需使用此代码将反序列化的xml转换为object.And之后只需使用模型来处理数据。这很简单

    public static T FromXml<T>(String xml)
    {
        T returnedXmlClass = default(T);

        try
        {
            using (TextReader reader = new StringReader(xml))
            {
                try
                {
                    returnedXmlClass =
                            (T)new XmlSerializer(typeof(T)).Deserialize(reader);
                }
                catch (InvalidOperationException)
                {
                    // String passed is not XML, simply return defaultXmlClass
                }
            }
        }
        catch (Exception ex)
        {
        }

        return returnedXmlClass;
    }

并使用

var model = FromXml<customer>(yourXmlString);

从XML文档中提取标记值C＃

2 个答案: