Question

大家度过美好的一天，只想询问Laravel学习像我这样的学生。

登录后，我可以访问此页面：

Route::get('/posts/{id}', 'PostController@showById');

当我退出并尝试再次访问该页面时，我收到提到的错误，我希望即使是访客也要显示帖子，但如果他们已退出，则不允许撰写帖子。

这是showById（）：

public function showById($id)
{
    $post = Post::find($id);

    return view('show-solo', compact('post'));
}

show-solo.blade.php

@extends('master')

@include('partials.nav-none')

@section('content')
    <div class="col-sm-8 blog-main">
        <div class="blog-post">

            @if ($flash = session('message'))
                <div class="alert alert-success flash-message" role="alert">
                    {{ $flash }}
                </div>
            @endif

            @if ( $post->user_id  == Auth::user()->id)
                <a href="/posts/{{ $post->id }}/delete">
                    <button class="btn-sm btn-warning post-btn" data-toggle="tooltip" data-placement="top" title="Delete Post"><i class="fa fa-times"></i></button>
                </a>
                <a href="/posts/{{ $post->id }}/edit">
                    <button class="btn-sm btn-primary post-btn" data-toggle="tooltip" data-placement="top" title="Edit Post"><i class="fa fa-pencil-square-o"></i></button>
                </a>
            @endif          

            <h2>Post number: {{ $post->id }}</h2>

            <h2 class="blog-post-title">
                <a class="title-link" href="/posts/{{ $post->id }}">{{ $post->title }}</a>
            </h2>

            <!-- {{ $post->created_at->toFormattedDateString() }} -->
            <p class="blog-post-meta">{{ $post->created_at->diffForHumans() }} by <a href="#">{{ $post->user->name }}</a></p>
            {{ $post->body }}

            <hr />

            @include('partials.error')

            @include('partials.post-comment')
        </div>
    </div>
@endsection

如果这有帮助，这是我的路线：

Route::get('/', function () {
    return view('welcome');
});

Route::get('/posts', 'PostController@index')->name('home');

Route::get('/posts/create', 'PostController@showForm');

Route::get('/posts/{id}', 'PostController@showById');

Route::get('posts/{id}/edit', 'PostController@editPostForm');

Route::get('posts/{id}/delete', 'PostController@deletePost');

Route::post('/posts', 'PostController@store');

Route::post('/posts/{post}/comments', 'CommentController@store');

Route::get('posts/{id}/delete', 'CommentController@deleteComment');

Route::post('/save-post', 'PostController@savePost');



Auth::routes();

Route::get('/home', 'HomeController@index');



Route::get('/register-user', 'RegistrationController@create');

Route::post('/register-user', 'RegistrationController@store');





Route::get('/login-user', ['as' => '/login-user', 'uses' => 'SessionController@create']);

Route::post('/login-user', 'SessionController@store');

Route::get('/logout-user', 'SessionController@destroy');

我做错了吗？即使我是访客，为什么我无法访问/发布/ {id}？那是什么＆＃34;试图获得非对象的属性＆＃34;消息是什么意思？

请告诉我是否应在此引用一些代码以帮助解决问题。

任何建议都将不胜感激。感谢。

Answer 1

您在以下行中收到错误

@if ( $post->user_id  == Auth::user()->id)

在视图中。

您在此行中收到错误的原因是您尝试访问经过身份验证的用户的ID，如Auth::user()->id。但是没有经过身份验证的用户。因此，Auth::user()调用返回null。您正试图访问id上的null。

尝试将其更改为

@if ( $post->user_id  == @Auth::user()->id)

OR

@if(Auth::user())
    @if ( $post->user_id  == Auth::user()->id)
    ...
    @endif
@endif

当没有签名时，ErrorException - 试图获取非对象的属性（查看：C：\ xampp \ ... \ show-solo.blade.php）

1 个答案: