从Ruby迁移到Java,我需要从多项响应中随机解析并获取一个字段。
这是我用来获取回复的ApiCall方法:
Response response = given().
headers(this.headers).
params(this.body).
when().
post(this.url).
then().
contentType(ContentType.JSON).
statusCode(200).
extract().
response();
它给了我这个JSON结构:
{
"Contents": {
"Title": "Search results",
"Count": "10",
"Page": "1",
"TotalCount": "1",
"TotalPages": 2,
"Genres": [
"Genre_1",
"Genre_2",
"Genre_3"
],
"Contents": [
{
"title": "content1_title",
"original_text": "original text 1",
"full_text": "Sample full sized text 1",
"short_text": "Sample short text 1",
"children_ids": {
"item": [
1,
2
]
},
"children_uuids": {
"item": [
"item1_uuid",
"item2_uuid"
]
},
"parent_ids": {
"item": [
1
]
},
"parent_uuids": {
"item": [
"item1_uuid"
]
},
"aired_from": "1994-01-01",
"aired_to": "1994-12-31",
"tags": {
"item": [
""
]
},
"available_condition1": 0,
"available_condition2": 1,
"price_condition1": "0.00",
"price_condition2": "13.00"
},
{
"title": "content2_title",
"original_text": "original text 2",
"full_text": "Sample full sized text 2",
"short_text": "Sample short text 2",
"children_ids": {
"item": [
1,
2
]
},
"children_uuids": {
"item": [
"item1_uuid",
"item2_uuid"
]
},
"parent_ids": {
"item": [
1
]
},
"parent_uuids": {
"item": [
"item1_uuid"
]
},
"aired_from": "1998-01-01",
"aired_to": "1998-01-31",
"tags": {
"item": [
""
]
},
"available_condition1": 0,
"available_condition2": 1,
"price_condition1": "0.00",
"price_condition2": "13.00"
}
]
},
"Success": true
}
问题是我需要随机获得#34;标题"至少有一个" children_uuids"从响应中的总数来看。
据我了解,步骤如下:
1)得到" Contents.Contents"的总大小。项目。 2)获得0到项目总数之间的随机数。 3)使用该数字选择一个带有" Contents.Contents。[n] .title"格式或类似。
尝试以下操作但没有成功:
JsonPath jsonPath = new JsonPath(response.toString());
List<?> list = jsonPath.getList("Contents.Contents.title.flatten()");
System.out.println(list);
这给了我以下错误:
io.restassured.path.json.exception.JsonPathException: Failed to parse the JSON document
作为参考,在Ruby中代码将是:
amount = @result['api_response']['Contents']['Contents'].count
amount = amount - 1
a = rand(0..amount)
while @result['api_response']['Contents']['Contents'][a]['children_uuids']['item'].nil? do
a = rand(0..amount)
#children_uuids = $result['api_response']['Contents']['Contents'][a]['children_uuids']
end
#price_hd = @result['api_response']['Contents']['Contents'][a]['price_hd']
content_title = @result['api_response']['Contents']['Contents'][a]['title']
更新:我已经让它部分工作了...我已经找到了一种方法从列表中选择一个项目:
String contentTitle = response.then().extract().path("Contents.Contents[0].title");
但是找不到使用这个jsonpath的方法
String contentTitle = response.then().extract().path("Contents.Contents.[?(@.children_uuids)].uuid");
第二行给了我:
java.lang.IllegalArgumentException:
Invalid JSON expression:
Script1.groovy: 1: unexpected token: [ @ line 1, column 45.
nRootObject.Contents.Contents.[?(@.child
^
提前致谢。
答案 0 :(得分:0)
在我看来,这在REST保证中很难做到,甚至可能是Java。
我建议你看看Karate(免责声明:我是开发者)。因此,您可以调用JavaScript函数来生成随机数,将其分配给变量,然后形成路径表达式以完全按照您的意愿执行:
Feature:
Scenario:
* def data = read('data.json')
* def size = (data.Contents.Contents.length)
* def index = Math.floor(Math.random() * size)
* print 'selected index: ' + index
* def item = (data.Contents.Contents[index])
* def children_uuids = item.children_uuids
* match children_uuids == { item: ['item1_uuid', 'item2_uuid'] }
答案 1 :(得分:0)
更新:我找到了一个包含以下代码的解决方案:
// get random content data
Integer contentAmmount = response.body().path("Contents.Contents.size()");
Random randomGenerator = new Random();
int randomInt = randomGenerator.nextInt(contentAmmount);
while (response.body().path(
String.join("", "Contents.Contents[", Integer.toString(randomInt),
"].children_uuids.item")).toString().isEmpty() ) {
randomInt = randomGenerator.nextInt(contentAmmount);
}
String contentTitle = response.then().extract()
.path(String.join("", "Contents.Contents[", Integer.toString(randomInt), "].title"));
String contentUuid = response.then().extract()
.path(String.join("", "Contents.Contents[", Integer.toString(randomInt), "].uuid"));
String contentChildrenUuid = response.body().path(
String.join("", "Contents.Contents[", Integer.toString(randomInt),
"].children_uuids.item"));