Question

我尝试编写一个导入所有用户的bash脚本，并为每个帐户执行一些操作。

a="some account"
b="some account" 
#... so on

USERS = #get imported

for ACCOUNT in $USERS; do
        if ["$ACCOUNT" == "$a"] || ["$ACCOUNT" == "$b"] || ["$ACCOUNT" == "$c"] || ["$ACCOUNT" == "$d"]; then
                echo "Skipping $ACCOUNT"
        else
                echo "this"
                echo "this $ACCOUNT"
        fi
done

但似乎有一个问题。对于每个帐户，我都会关注：

[thisis @ anaccount：not found

我尝试删除单个括号并将整个if子句放入双括号中，但这会导致相同的错误。

我还删除了每个变量调用的双引号，但这似乎不是问题。

有人可以提供建议吗？

Answer 1

你只是缺少一些空间......

#!/bin/bash 
a="ACC_A"
b="ACC_B" 
c="ACC_C"
d="ACC_D"

USERS="ACC_A ACC_B ACC_C ACC_X ACC_Y ACC_Z" 

for ACCOUNT in $USERS; do
        if [ "$ACCOUNT" = "$a" ] || [ "$ACCOUNT" = "$b" ] || [ "$ACCOUNT" = "$c" ] || [ "$ACCOUNT" = "$d" ]; then
              echo "Skipping $ACCOUNT"
    else
              echo "this $ACCOUNT"
    fi
done

并快速测试：

$ bash accounts.sh 
Skipping ACC_A
Skipping ACC_B
Skipping ACC_C
this ACC_X
this ACC_Y
this ACC_Z

用if-else语句循环的Bash脚本

1 个答案: