java - end loop when user types "N"

Question

When the user selects yes, it loops and starts again. When the user selects N, it should end the program but I am not sure what I am missing here. This is a program to tell you the x and y values when giving the slope and y-intercept to the program.

Java file

        int slope;
        int yintercept;
        String newEquation;
        boolean play = true; 


        System.out.print("Enter the slope: ");
        slope = input.nextInt();

        System.out.print("Enter y-intercept: ");
        yintercept = input.nextInt();

        System.out.printf("The equation of the line is: y = %dx + %d", slope, yintercept);

        System.out.print("\nWould you like to create a new equation... Y or N? ");
        newEquation = input.next();


            while (play)
            {
                if (newEquation.equals("Y"))
                {
                    System.out.print("Enter the slope: ");
                    slope = input.nextInt();

                    System.out.print("Enter y-intercept: ");
                    yintercept = input.nextInt();

                    System.out.printf("The equation of the line is: y = %dx + %d", slope, yintercept);

                    System.out.print("\nWould you like to create a new equation... Y or N? ");
                    newEquation = input.next();
                }
                if (newEquation.equals("N")){
                    play =false; 

                }
                else{
                    System.out.print("Enter the slope: ");
                    slope = input.nextInt();

                    System.out.print("Enter y-intercept: ");
                    yintercept = input.nextInt();

                    System.out.printf("The equation of the line is: y = %dx + %d", slope, yintercept);

                    System.out.print("\nWould you like to create a new equation... Y or N? ");
                    newEquation = input.next();
                }





            }
    }   
}

Answer 1

为什么在 if（newEquation.equals（“Y”））和 else 部分中使用相同的代码？如果您希望用户只输入“Y”或“N”，那么您可以将其他内容放在fron中，如下所示： else if(newEquation.equals("N")) 并删除其他部分。

因为你编写它的方式，它测试输入是否为“Y”，然后在同一循环迭代中第二次测试输入是否为“N”，这意味着你的程序采用斜率当它通过循环时，信息两次，因为else仅指“N”。

Answer 2

尝试一个do-while构造，以及一个equalsIgnoreCase（制作＆＃34; y＆＃34;和＆＃34; Y＆＃34;两者都针对＆＃34; Y＆＃34; ）。

int slope;
int yintercept;
String newEquation;
boolean play = true; 


do
{
    System.out.print("Enter the slope: ");
    slope = input.nextInt();

    System.out.print("Enter y-intercept: ");
    yintercept = input.nextInt();

    System.out.printf("The equation of the line is: y = %dx + %d", slope, yintercept);

    System.out.print("\nWould you like to create a new equation... Y or N? ");
    newEquation = input.next();
} while newEquation.equalsIgnoreCase("Y")

（我只剪了你的线，但没有编译和测试。如果我错过了什么，我道歉。）

do-while测试用户是否在第一轮之后键入了Y / y。请注意，用户不必键入N / n，而是可以键入q，以便循环终止。