Question

尽管输出与预期输出完全相同，但仍会出现此错误消息。

*错误：预计会在可用字母行中找到一个数字：abcdefghijklmnopqrstuvwxyz。检查以确保您的线与预期输出匹配！ *

我的代码：

def hangman(secretWord):
    print ("Welcome to the game, Hangman!")
    print ("I am thinking of a word that is " + str(len(secretWord)) + " letters long" )

    lettersGuessed=[]
    guesses = 8
    p = " "
    while guesses > 0:

        print ("You have " + str(guesses) + " guesses left")

        print ("Available Letters: " + str(getAvailableLetters(lettersGuessed))),

        user_input = input("Please guess a letter: ")
        user_input = str(user_input)
        user_input = user_input.lower()

        if user_input  in lettersGuessed:
            print ("Oops! You've already guessed that letter: " + str(getGuessedWord(secretWord, lettersGuessed)))
        else:
            lettersGuessed.append(user_input)
            if user_input in secretWord:
                print ("Good guess: " + str(getGuessedWord(secretWord,lettersGuessed)))
                if isWordGuessed(secretWord, lettersGuessed):
                    break
                else: continue
            else:
                print("Oops! That letter is not in my word: " + str(getGuessedWord(secretWord, lettersGuessed)))
                guesses = guesses - 1
    p = str(getGuessedWord(secretWord, lettersGuessed))
    p = p.split(" ")
    p = "".join(p)
    p = str(p)

    if p == secretWord:
        print ("Congratulations, you won!")
        return
    else:
        print ("Sorry, you ran out of guesses. The word was " + secretWord + ".")
        return

Answer 1

检查每一行和“be sure your lines match up with the expected output”。检查输出的自动化系统可能需要输出行必须完全匹配他们的“correct output”包括 -----------行，以及你的代码不打印那些行。

轻松：

print ("I am thinking of a word that is " + str(len(secretWord)) + " letters long" )
print ("-----------")   ### <---- Add this one line
lettersGuessed=[]

和

print ("Good guess: " + str(getGuessedWord(secretWord,lettersGuessed)))
print ("-----------")   ### <---- Add this one line
if isWordGuessed(secretWord, lettersGuessed):

您可能需要在代码中的其他条件中添加一行，如else:条件。

为了使调试更容易，重复次数更少，代码更清晰，您可以将输出分配给变量并在需要时打印：

def hangman(secretWord):
    line_break = "-----------"
    ...
    print ("I am thinking of a word that is " + str(len(secretWord)) + " letters long" )
    print (line_break)

等。

希望这有帮助。

尽管输出正确但仍然出错

1 个答案: