Question

我有2个字符串数组，

  str1[] = {"a","b","aa","c"}

和

  str2[] = {"aa","a","b","c","d"}

如果在string []，预期结果，str3 [] = {“d”}

中存在，我如何比较和删除值？

提前致谢

Answer 1

在这些操作之后，

ts1将在其中包含“d”。

String str1[] = {"a","b","aa","c"}; String str2[] = {"aa","a","b","c","d"}; TreeSet ts1 = new TreeSet(Arrays.asList(str2)); ts1.removeAll(Arrays.asList(str1));

Answer 2

将数组转换为列表并将它们添加到一个将自动删除重复项的集合中。使用Set接口的toArray（）方法将元素作为数组获取。

    String[] str1 = {"a","b","aa","c"};
    String[] str2 = {"aa","a","b","c","d"};

    Set set = new HashSet();
    set.addAll(Arrays.asList(str1));//add first array to set, removes duplicates
    set.addAll(Arrays.asList(str2));//add second array to set, removes duplicates
    String[] str3 = (String[])set.toArray(new String[set.size()]);//convert back to array

如何比较2个java字符串数组并删除如果具有相同的值

2 个答案: