我们假设我有一个不同订单的商店。订单有送货地址和发票地址。地址本身有一个城市,街道等:
let data = [
{ id: 1, name: 'Anna', delivery: {city: "Amsterdam"}, invoice: {city: "Amsterdam"} },
{ id: 2, name: 'Anton', delivery: {city: "Amsterdam"}, invoice: {city: "Berlin"}}
];
我想过滤所有送货地址和发票地址都相同的订单。
我在jsFiddle中尝试过这个:https://jsfiddle.net/gbwv2bde/3/,但我对结果并不满意。有人知道使用Filter进行该任务的方法吗?
答案 0 :(得分:1)
试试这个,它会返回项目Anna和Julie
var data = [
{ id: 1, name: 'Anna', delivery: { city: "Amsterdam" }, invoice: { city: "Amsterdam" } },
{ id: 2, name: 'Anton', delivery: { city: "Amsterdam" }, invoice: { city: "Berlin" } },
{ id: 3, name: 'John', delivery: { city: "Berlin" }, invoice: { city: "Paris" } },
{ id: 4, name: 'Julie', delivery: { city: "Paris" }, invoice: { city: "Paris" } }
];
var myStore = new Memory({ data: data, idProperty: 'id' });
var myResultsSet = myStore.filter(function (object) {
return object.delivery.city === object.invoice.city;
});
myResultsSet.forEach(function (item) {
console.log("item ", item.name);
});
基本上你可以创建一个自己的函数传递给filter(),你可以用它来编写自己的比较逻辑。
请点击此处了解更多详情 https://github.com/SitePen/dstore/blob/master/docs/Collection.md
过滤器(查询)
这会过滤集合,返回新的子集集合。该 query可以是具有属性的对象或过滤器对象 定义匹配对象的约束。有些商店,比如服务器 或者RQL存储,可以接受基于字符串的查询。内存中的商店 功能(如dstore / Memory)可以接受过滤功能 同样,但使用过滤器构建器将确保最大 跨店兼容性。
编辑:包含更多要比较的属性的示例。您的函数只需返回true或false(如果对象与您的比较条件匹配,则为true)
var data = [
{ id: 1, name: 'Anna', delivery: { city: "Amsterdam", price: 5 }, invoice: { city: "Amsterdam", price: 20 } },
{ id: 2, name: 'Anton', delivery: { city: "Amsterdam", price: 8 }, invoice: { city: "Berlin", price: 7 } },
{ id: 3, name: 'John', delivery: { city: "Berlin", price: 10 }, invoice: { city: "Paris", price: 20 } },
{ id: 4, name: 'Julie', delivery: { city: "Paris", price: 2 }, invoice: { city: "Paris", price: 3 } }
];
//example for custom filtering with nested properties
var myStore = new Memory({ data: data, idProperty: 'id' });
var myResultsSet = myStore.filter(function (object) {
if(object.delivery.city === object.invoice.city){
if (object.delivery.price < 5 && object.invoice.price < 5)
return true;
}else
return false;
});
myResultsSet.forEach(function (item) {
console.log("item ", item.name);
});