Question

我正在构建API并使用表单进行数据绑定，现在我希望能够传递实体的ID，获取引用并将其附加到项目，这是一个示例：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder->add('credit');
    $builder->add('currency', 'currency');
    $builder->add('borrower', BorrowerType::class, [
        'required' => true
    ]);

    $builder->addEventListener(FormEvents::PRE_SUBMIT, function (FormEvent $event) {
        $data = $event->getData();
        $borrower = $this->em->getReference(Borrower::class, $data['borrower']);
        $data['borrower'] = $borrower;
    });
}

返回＆＃34;错误：此值无效。\ n＆＃34;

这是我的测试请求：

    $client->request('POST', $endpoint, [
        'loan' => [
            'credit' => '1000',
            'currency' => 'EUR',
            'borrower' => $borrower->getId()
        ]
    ]);

Answer 1

“$ event-＆gt; getData（）”是您的实际实体，如果此表单在其选项解析程序中使用默认实体，或者您在制作表单时通过控制器传递实体。

public function buildForm(FormBuilderInterface $builder, array $options)
 {
    $builder->add('credit');
    $builder->add('currency', 'currency');
    $builder->add('borrower', BorrowerType::class, [
         'required' => true
    ]);

    $builder->addEventListener(FormEvents::PRE_SUBMIT, function (FormEvent $event) {
        $entity = $event->getData();

         //The following doesn't make a lot of sense
         //The borrower will already be set

        $borrower = $this->em->getReference(Borrower::class, $entity->getBorrower());
        $entity->setBorrower($borrower);
    });
 }

就像用这种检查用户是否必须输入密码的标准方式（如果它们是新的）一样，或者如果用户已经存在则不需要输入密码。

$builder->addEventListener(FormEvents::PRE_SET_DATA, function (FormEvent $event) {
        $user = $event->getData();
        $form = $event->getForm();
        $formParams = [
            'type' => PasswordType::class,
            'first_options' => ['label' => 'Password'],
            'second_options' => ['label' => 'Repeat Password'],
        ];

        if ((!$user || null === $user->getId())) {
            $formParams['constraints'] = new NotBlank();
        } else {
            $formParams['required'] = false;
        }

        $form->add('plainPassword', RepeatedType::class, $formParams);
    });

如果此表单正在创建或更新实体，则借用者信息在创建时设置为实体。

Answer 2

一种直接的方法来达到这个＆＃34; symfonic＆＃34;方法是使用DataTransformer

DataTransformer将采用数据格式并将其转换为另一种格式（类型）。

您可以使用的是ViewTransformer Transform()，在id阶段，将获取实体并返回其ReverseTransform()，而在id中则需要class BorrowerToIdTransform implements DataTransformerInterface { private $manager; public function __construct(ObjectManager $manager) { $this->manager = $manager; } /** * Transforms an object (Borrower) to a string (id). * * @param Borrower|null $issue * @return string */ public function transform($borrower) { if (null === $borrower) { return ''; } return $borrower->getId(); } /** * Transforms a string (id) to an object (Borrower). * * @param string $id * @return Borrower|null * @throws TransformationFailedException if object (issue) is not found. */ public function reverseTransform($id) { if (!$id) { return; } $borrower = $this->manager ->getRepository(Borrower::class) ->find($id) ; if (null === $borrower) { throw new TransformationFailedException(sprintf( 'A borrower with "%s" id does not exist!', $id )); } return $issue; } }并且，通过使用存储库，将检索实体。

像

这样的东西

 @Repository
 public class OhlcDaoImpl implements OhlcDao {

@Autowired
SessionFactory sessionFactory;
Session session;

 public List getOhlc(Result result) {
    session = sessionFactory.openSession();
 SQLQuery query = session.createSQLQuery("EXEC getOhlc :stockSymbol, :statementType, :financialDataTypeId, :fiscalYearId");
 query.setString("stockSymbol",result.getStockSymbol());
 query.setString("statementType",result.getStatementType());
 query.setInteger("financialDataTypeId",result.getFinancialDataTypeId());
 query.setInteger("fiscalYearId",result.getFiscalYearId());

 List l = query.list();
return l;
}
}

Symfony3表单类型，通过id引用其他实体

2 个答案: