Question

我被要求从SQL Server获取数据，特定小时的时间间隔为5分钟，这是当天发布数据的高峰时间。我设法在单独的查询中获得特定日期的高峰时段。

我使用以下查询来获取5分钟间隔的数据

select  
    count(pbcnt) as county, --MIN(pubpeakhr) ,
    cast(MIN(DATEPART(HOUR,pubpeakhr)) as varchar) + ':00  -  '  + RIGHT('0'  +   cast(MIN(DATEPART(MINUTE,pubpeakhr) + 5) as varchar), 2) + ':00' 
from 
    (select   
         count(pub_cnt) pbcnt,
         CONVERT(CHAR(19), CONVERT(SMALLDATETIME, dateadd(hh,
         CASE WHEN 
             time >= '3/' + CAST((8-DATEPART(dw,'3/1/' + CAST(YEAR  (time) as varchar)))%7 + 8 as varchar) +  '/' + CAST(YEAR(time) as varchar) + ' 7:00' 
           AND 
             time < '11/' + CAST((8-DATEPART(dw,'11/1/' + CAST(YEAR(time) as varchar)))%7 + 1 as varchar) +  '/' + CAST(YEAR(time) as varchar) + ' 6:00' 
         THEN -4 ELSE -5 END, time) , 121),121 ) as pubpeakhr
    from 
        tblpub ev   
    INNER JOIN 
        tblver v ON ev.id= v.id
    Where 
        1=1 and  v.time>= '2016-05-01'     
    group by  
        v.time) aa
where  
    1=1
    and (pubpeakhr) >= '2017-03-07 10:00:00'
    and (pubpeakhr) <= '2017-03-07 10:59:59' 
group by  
    (DATEPART(MINUTE, pubpeakhr) / 5)   
order by 2

内部查询的输出将是这样的，

输出：

请帮我构建sql以获得第2列所需的输出。

注意：column1（县）是正确的。

先谢谢

Answer 1

由于我没有输入记录，因此我将输出视为临时表，并在此基础上编写逻辑。你也可以遵循同样的事情。

    create table #tmp1
(
counts int,
timeperiod smalldatetime
)
insert into #tmp1 values (3,'3/7/2017 10:02'),(37,'3/7/2017 10:05'),(2,'3/7/2017 10:06'),(28,'3/7/2017 10:09'),
            (32,'3/7/2017 10:11'),(1,'3/7/2017 10:17'),(31,'3/7/2017 10:20'),(22,'3/7/2017 10:23'),(22,'3/7/2017 10:24'),
            (44,'3/7/2017 10:26'),(2,'3/7/2017 10:31')
;with CTE as 
(select left(RIGHT(T1.timeperiod,7),2) + ':' + 
       IIF(LEN(cast((row_number() over (order by timeperiod)-1) * 5 as varchar(2)))=1, 
           '0'+cast((row_number() over (order by timeperiod)-1) * 5 as varchar(2)),
            cast((row_number() over (order by timeperiod)-1) * 5 as varchar(2))
           ) starttime, 
       left(RIGHT(T1.timeperiod,7),2)+':'+ 
       IIF(LEN(cast((row_number() over (order by timeperiod)) * 5 as varchar(2)))=1, 
           '0'+cast((row_number() over (order by timeperiod)) * 5 as varchar(2)),
            cast((row_number() over (order by timeperiod)) * 5 as varchar(2))
           ) endtime 
from  #tmp1 T1
)
select sum(T.counts) counts, starttime +  '- ' + endtime peakhour 
from CTE C inner join  #tmp1 T on T.timeperiod > cast(left(timeperiod,11)+' ' +C.starttime as smalldatetime) and 
T.timeperiod <= cast(left(timeperiod,11)+' ' +C.endtime as smalldatetime)
group by starttime +  '- ' + endtime

drop table #tmp1

在SQL 2012中的select语句中编写Time Interval gap（比如说5分钟，即10:05 - 10:10）需要帮助

1 个答案: