Question

所以我试图通过输入不同的单元格使我的代码打印出某个列。所以我设计了我的代码，让一个人输入五种不同类型的电影，然后openpyxl遍历excel文件，查找五部电影并打印出整行，但事情是它不断吐出错误，我不知道知道如何解决它

输出：

Traceback (most recent call last):
File "C:/Users/Shay/PycharmProjects/untitled/Assignment ITN.py", line 39, in <module>
   listcreator(movieID)
File "C:/Users/Shay/PycharmProjects/untitled/Assignment ITN.py", line 28, in listcreator
   if sheet.cell(row=r, column=c).value == movieOne:
AttributeError: 'Workbook' object has no attribute 'cell'

这是我的代码：

import csv
import openpyxl
from openpyxl import load_workbook

movieID = openpyxl.load_workbook(filename="C:/Users/Shay/Downloads/Movie IDs - Student Copy.xlsx")
movie_ID = movieID.active


movie_ID_List = []
movie_Ratings_list = []
mveavg = []

movieOne = input("Type first Movie\n")
movieTwo = input("Type in second movie\n")
movieThree = input("Type in third movie\n")
movieFour = input("Type in fourth movie\n")
movieFive = input("Type in fifth movie\n")

movieOneList = []
movieTwoList = []
movieThreeList = []
movieFourList = []
movieFiveList = []

def listcreator(sheet):
    for r in range(1, 27278):
        for c in range(1,2):
            if sheet.cell(row=r, column=c).value == movieOne:
                movieOneList.append(sheet.cell(row=r, column=0))
            if sheet.cell(row=r, column=c).value == movieTwo:
                movieTwoList.append(sheet.cell(row=r, column=0))
            if sheet.cell(row=r, column=c).value == movieThree:
                movieThreeList.append(sheet.cell(row=r, column=0))
            if sheet.cell(row=r, column=c).value == movieFour:
                movieFourList.append(sheet.cell(row=r, column=0))
            if sheet.cell(row=r, column=c).value == movieFive:
                movieFiveList.append(sheet.cell(row=r, column=0))

listcreator(movieID)

print(movieOneList)
print(movieTwoList)
print(movieThreeList)
print(movieFourList)
print(movieFiveList)
movieOneList - (movieOneList[0])
movieTwoList - (movieTwoList[0])
movieThreeList - (movieThreeList[0])
movieFourList - (movieFourList[0])
movieFiveList - (movieFiveList[0])
print(movieOneList)
print(movieTwoList)
print(movieThreeList)
print(movieFourList)
print(movieFiveList)

我还应该提一下，我是一个菜鸟编码器，所以如果这个问题看起来很基本但是很乐意帮助，我很抱歉

Answer 1

你应该给你的变量更好的名字。

listcreator函数接受一个Worksheet对象。但是当你调用它时，你传递的是movieID，这是你在顶部加载的工作簿对象，而不是movie_ID，这是该书中的活动工作表。

如果你把这些对象称为更合适的东西，你就可以更容易地看到你做错了什么。

Openpyxl：AttributeError：'Workbook'对象没有属性'cell'

1 个答案: