Question

如何将对象转换为二维数组？

例如：

{ field : 'name',
  value : 'peter',
  field1 : 'email',
  value1 : 'test@gmail.com',
  field2 : 'id',
  value2 : '2345',
  ............
  .....
  ...
 }

到

  [['name', 'peter],['email','test@gmail.com'],['id','2345'] .......]

谢谢！

Answer 1

您可以查看field并获取新数组的值。

＆＃13;

var object = { field: 'name', value: 'peter', field1: 'email', value1: 'test@gmail.com', field2: 'id', value2: '2345'},
    array = Object.keys(object).reduce((r, k) => 
        r.concat(k.slice(0, 5) === 'field'? [[object[k], object['value' + k.slice(5)]]] : [])
    , []);

console.log(array);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 2

let obj = {
  field: 'name',
  value: 'peter',
  field1: 'email',
  value1: 'test@gmail.com',
  field2: 'id',
  value2: '2345'
};

let result = Object.keys(obj)
  .filter(key => key.indexOf("field") === 0)  // we're only interested in the "fieldX" keys
  .map(field => [obj[field], obj[field.replace("field", "value")]]); // build the array from the "fieldX"-keys

console.log(result);

Answer 3

＆＃13;

    let obj = {
      field : 'name',
      value : 'peter',
      field1 : 'email',
      value1 : 'test@gmail.com',
      field2 : 'id',
      value2 : '2345'
    };
    
    let results = [];

    Object.values(obj).forEach((e, i, arr) => {
    	if (!(i % 2)) {
    		results.push([e, arr[i+1]]);
    	}
    });

    console.log(results);

＆＃13;

Answer 4

尝试此功能，它将为您完成：

var objectToPairs = function(object) {
  var array = [];

  for (var key in object) {
    if (object.hasOwnProperty(key)) {
      if (key.indexOf('field') === 0) {
        var index = key.replace(/^\D+/g, '');
        var valueKey = 'value' + index;

        if (object.hasOwnProperty(key)) {
          array.push([object[key], object[valueKey]]);
        }
      }
    }
  }

  return array;
}

JSFIddle：

https://jsfiddle.net/mucwvqpz/1/

将对象转换为2d数组

4 个答案: