当我使用多列的pluck时，我得到了这个：
{"Kreis 1 \/ Altstadt":"City","Kreis 2":"Enge","Kreis 3":"Sihifeld","Kreis 4":"Hard","Kreis 5 \/ Industriequartier":"Escher Wyss","Kreis 6":"Oberstrass","Kreis 7":"Witikon","Kreis 8 \/ Reisbach":"Weinegg","Kreis 9":"Altstetten","Kreis 10":"Wipkingen","Kreis 11":"Seebach","Kreis 12 \/ Schwamendingen":"Hirzenbach"
但我需要这个吗？
["Rathaus","Hochschulen","Lindenhof","City","Wollishofen","Leimbach","Enge","Alt-Wiedikon","Friesenberg","Sihifeld","Werd","Langstrasse","Hard","Gewerbechule","Escher Wyss","Unterstrass","Oberstrass","Fluntern","Hottingen","Hirslanden","Witikon","Seefeld","M\u00fchlebach","Weinegg","Albisrieden","Altstetten","H\u00f6ngg","Wipkingen","Affoltern","Oerlikon","Seebach","Saatlen","Schwamendingen-Mitte","Hirzenbach"]
任何建议我该怎么做？这是我的方法：
public function autocomplete_districts(Request $request)
{
$district = $request->input('query');
// $ass = /DB::table('districts')->select(array('district', 'region'))->get();
// dd($ass);
$data = Districts::whereRaw('LOWER(district) like ?', [strtolower('%'.$district . '%')])->orWhereRaw('LOWER(region) like ?', [strtolower('%'.$district . '%')])->pluck('region','district');
return response()->json($data);
}
答案 0 :(得分：17)
您应该select()使用get()，然后根据需要修改对象。
所以代替：->pluck('region','district');
使用：->select('region','district')->get();
pluck()。
尽可能地，你应该让你的模型单数形式而不是复数（区） - 遵循Laravel命名法。
答案 1 :(得分：6)
这就是采摘的方式。而是试试这个。
$data = Districts::whereRaw('LOWER(district) like ?', [strtolower('%'.$district . '%')])->orWhereRaw('LOWER(region) like ?', [strtolower('%'.$district . '%')])->select('region', 'district')->get();
$data = collect($data->toArray())->flatten()->all();
答案 2 :(得分：2)
这是我一直面临的问题，导致我创建了可以在模型或数组上使用的以下解决方案。
还支持点语法，该语法将根据需要创建多维数组。
在AppServiceProvider（或您选择的任何提供程序）中注册此宏：
/**
* Similar to pluck, with the exception that it can 'pluck' more than one column.
* This method can be used on either Eloquent models or arrays.
* @param string|array $cols Set the columns to be selected.
* @return Collection A new collection consisting of only the specified columns.
*/
Collection::macro('pick', function ($cols = ['*']) {
$cols = is_array($cols) ? $cols : func_get_args();
$obj = clone $this;
// Just return the entire collection if the asterisk is found.
if (in_array('*', $cols)) {
return $this;
}
return $obj->transform(function ($value) use ($cols) {
$ret = [];
foreach ($cols as $col) {
// This will enable us to treat the column as a if it is a
// database query in order to rename our column.
$name = $col;
if (preg_match('/(.*) as (.*)/i', $col, $matches)) {
$col = $matches[1];
$name = $matches[2];
}
// If we use the asterisk then it will assign that as a key,
// but that is almost certainly **not** what the user
// intends to do.
$name = str_replace('.*.', '.', $name);
// We do it this way so that we can utilise the dot notation
// to set and get the data.
array_set($ret, $name, data_get($value, $col));
}
return $ret;
});
});
然后可以按以下方式使用它：
$a = collect([
['first' => 1, 'second' => 2, 'third' => 3],
['first' => 1, 'second' => 2, 'third' => 3]
]);
$b = $a->pick('first', 'third'); // returns [['first' => 1, 'third' => 3], ['first' => 1, 'third' => 3]]
或者，在任何型号上，您都可以拥有：
$users = User::all();
$new = $users->pick('name', 'username', 'email');
// Might return something like:
// [
// ['name' => 'John Doe', 'username' => 'john', 'email' => 'john@email.com'],
// ['name' => 'Jane Doe', 'username' => 'jane', 'email' => 'jane@email.com'],
// ['name' => 'Joe Bloggs', 'username' => 'joe', 'email' => 'joe@email.com'],
// ]
也可以使用点表示法以及as [other name]语法来引用任何关系：
$users = User::all();
$new = $users->pick('name as fullname', 'email', 'posts.comments');
// Might return something like:
// [
// ['fullname' => 'John Doe', 'email' => 'john@email.com', 'posts' => [...]],
// ['fullname' => 'Jane Doe', 'email' => 'jane@email.com', 'posts' => [...]],
// ['fullname' => 'Joe Bloggs', 'email' => 'joe@email.com', 'posts' => [...]],
// ]
答案 3 :(得分：0)
Laravel：要在单独的数组中使用多列，请使用以下代码。
$Ads=Ads::where('status',1);
$Ads=$Ads->where('created_at','>',Carbon::now()->subDays(30));
$activeAdsIds=$Ads->pluck('id'); // array of ads ids
$UserId=$Ads->pluck('user_id'); // array of users ids
答案 4 :(得分：0)
我在LARAVEL 5.6中的解决方案：
您好，我遇到了同样的问题，我需要将2列合并到1个选择列表中。 我的数据库有2个用于用户的列：first_name和last_name。 我需要一个选择框，其中要显示用户的全名，并将id作为值。 这是我使用pluck（）方法修复的方式：
在用户模型中，我创建了一个全名访问器功能：
public function getNameAttribute() {
return ucwords($this->last_name . ' ' . $this->first_name);
}
之后，要使用全名和对应的数据库ID作为值填充选择列表，我在返回视图的控制器中使用了此代码（不显示已存档的用户，但是您可以更改查询的开始如果愿意，最重要的是get（）和pluck（）函数：
$users = User::whereNull('archived_at')
->orderBy('last_name')
->get(['id','first_name','last_name'])
->pluck('name','id');
return view('your.view', compact('users'));
现在，您可以在选择列表中使用$ users！
因此，首先，您需要从数据库中获取所有值， 之后，您可以使用在PLUCK方法中定义的任何访问器属性，
只要访问器所需的所有列都在GET中；-）
答案 5 :(得分：0)
对不起，我迟到了几天之前也遇到了同样的情况
我已经创建了模型作用域
有关范围的更多信息
https://laravel.com/docs/5.8/eloquent#query-scopes
https://medium.com/@janaksan_/using-scope-with-laravel-7c80dd6a2c3d
/**
* Scope a query to Pluck The Multiple Columns
*
* This is Used to Pluck the multiple Columns in the table based
* on the existing query builder instance
*
* @author Manojkiran.A <manojkiran10031998@gmail.com>
* @version 0.0.2
* @param \Illuminate\Database\Eloquent\Builder $query
* @param string $keyColumn the columns Which is used to set the key of array
* @param array $extraFileds the list of columns that need to plucked in the table
* @return \Illuminate\Support\Collection
* @throws Illuminate\Database\QueryException
**/
public function scopePluckMultiple( $query, string $keyColumn, array $extraFileds):\Illuminate\Support\Collection
{
//pluck all the id based on the query builder instance class
$keyColumnPluck = $query->pluck( $keyColumn)->toArray();
//anonymous callback method to iterate over the each fileds of table
$callBcakMethod = function ($eachValue) use ($query)
{
$eachQuery[$eachValue] = $query->pluck( $eachValue)->toArray();
return $eachQuery;
};
//now we are collapsing the array single time to get the propered array
$extraFields = \Illuminate\Support\Arr::collapse( array_map($callBcakMethod, $extraFileds));
// //iterating Through All Other Fileds and Plucking it each Time
// foreach ((array)$extraFileds as $eachFiled) {
// $extraFields[$eachFiled] = $query->pluck($eachFiled)->toArray();
// }
//now we are done with plucking the Required Columns
//we need to map all the values to each key
//get all the keys of extra fileds and sets as array key or index
$arrayKeys = array_keys($extraFields);
//get all the extra fileds array and mapping it to eack key
$arrayValues = array_map(
function ($value) use ($arrayKeys) {
return array_combine($arrayKeys, $value);
},
call_user_func_array('array_map', array_merge(
array(function () {
return func_get_args();
}),
$extraFields
))
);
//now we are done with the array now Convert it to Collection
return collect( array_combine( $keyColumnPluck, $arrayValues));
}
现在是测试部分
基本示例
$basicPluck = Model::pluckMultiple('primaryKeyFiles',['filedOne', 'FiledTwo']);
高级示例
$advancedPlcuk = Model::whereBetween('column',[10,43])
->orWhere('columnName','LIKE', '%whildCard%')
->Where( 'columnName', 'NOT LIKE', '%whildCard%')
->pluckMultiple('primaryKeyFiles',['filedOne', 'FiledTwo']);
但是它返回 \ Illuminate \ Support \ Collection ，所以
如果您需要转换为数组
$toArrayColl = $advancedPlcuk->toArray();
如果您需要转换为json
$toJsonColl = $advancedPlcuk->toJson();
答案 6 :(得分：0)
要回答“如何使用pluck（类似）返回多列”这一特定问题，我们必须记住Pluck是Collection成员函数。因此，如果我们坚持提出的问题，我们应该坚持基于集合的答案（您可能会发现开发基于模型的解决方案更有益，但这无助于解决所提出的问题）。
Collection类提供了“ map”成员函数，可以解决所提出的问题：
$data = Districts::whereRaw('LOWER(district) like ?', [strtolower('%'.$district . '%')])->orWhereRaw('LOWER(region) like ?', [strtolower('%'.$district . '%')])
->map(function ($item, $key, $columns=['region','district']) {
$itemArray = [];
foreach($columns as $column){
$itemArray[$column] = $item->$column;
}
return ($itemArray);
});
dd($data);
这应该给您一个集合，其中每个元素是一个由“ region”和“ district”索引的2元素数组。
答案 7 :(得分：0)
到目前为止，Laravel 没有提供这样的宏来选择特定的列，但无论如何 Laravel 是开箱即用的，让我们几乎可以自定义所有内容。
在 Laravel 8.x 中测试
在 AppServiceProvider.php 中
use Illuminate\Support\Collection;
// Put this inside boot() function
Collection::macro('pick', function (... $columns) {
return $this->map(function ($item, $key) use ($columns) {
$data = [];
foreach ($columns as $column) {
$data[$column] = $item[$column] ?? null;
}
return $data;
});
});
用法
$users = App\Models\User::all();
$users->pick('id','name');
// Returns: [['id' => 1, 'name' => 'user_one'],['id' => 2, 'name' => 'user_two']]
重要说明：