我希望在我的网站上的用户注册后出现一个包含欢迎消息等的框。但是，只要点击一个按钮就可以显示它，我希望它在电子邮件，密码，用户名等发送到数据库时发生。所以，而不是这样做：
<button onclick="document.getElementById('id01').style.display='block'" style="width:auto;">Login</button>
我有什么方法可以通过编程方式完成此操作吗？我也尝试过：
<script>
self = function(id01)
</script>
但它无法正常工作。关于我应该尝试/做什么的任何提示？
这是我将信息发送到我的数据库的方式：
//if no errors have been created carry on
if(!isset($error)){
$hashedpassword = $user->password_hash($_POST['password'], PASSWORD_BCRYPT);
$activasion = md5(uniqid(rand(),true));
try {
$stmt = $db->prepare('INSERT INTO members (username,password,email,active) VALUES (:username, :password, :email, :active)');
$stmt->execute(array(
':username' => $_POST['username'],
':password' => $hashedpassword,
':email' => $_POST['email'],
':active' => $activasion
));
$id = $db->lastInsertId('memberID');
//send email
$to = $_POST['email'];
$subject = "Registration Confirmation";
$body = "<p>Thank you for registering at Game World.</p>
<p>To activate your account, please click on this link: <a href='".DIR."activate.php?x=$id&y=$activasion'>".DIR."activate.php?x=$id&y=$activasion</a></p>
<p>Regards Site Admin</p>";
$mail = new Mail();
$mail->setFrom(SITEEMAIL);
$mail->addAddress($to);
$mail->subject($subject);
$mail->body($body);
$mail->send();
//redirect to index page
header('Location: index.php?action=joined');
?>
答案 0 :(得分：0)
你可以通过多种方式实现你想要的结果，js警报，jquery弹出。引导模态。
选项1：
使用jquery和jquery ui
<!-- latest stable jquery -->
<script src="https://code.jquery.com/jquery-3.2.1.min.js" integrity="sha256-hwg4gsxgFZhOsEEamdOYGBf13FyQuiTwlAQgxVSNgt4=" crossorigin="anonymous"></script>
<!-- latest stable jquery ui -->
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.min.js" integrity="sha256-VazP97ZCwtekAsvgPBSUwPFKdrwD3unUfSGVYrahUqU=" crossorigin="anonymous"></script>
<?php
if(isset($_GET['action']) && !empty($_GET['action'])){
$action = $_GET['action'];
if($action == "joined"){?>
<div id="modal" style="display: none;">
This is pop up, add message.
</div>
<script type="text/javascript">
$(document).ready(function () {
$("#modal").dialog();
});
</script>
<?php
}else{
//action != joined do something
}
}else{
//$GET NOT set do something
}
选项2： 使用Bootstrap
<!-- latest stable jquery -->
<script src="https://code.jquery.com/jquery-3.2.1.min.js" integrity="sha256-hwg4gsxgFZhOsEEamdOYGBf13FyQuiTwlAQgxVSNgt4=" crossorigin="anonymous"></script>
<!-- Bootstrap links -->
<?php
if(isset($_GET['action']) && !empty($_GET['action'])){
$action = $_GET['action'];
if($action == "joined"){?>
<div class="modal fade" id="success">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-body">
<div class="alert alert-block alert-success">
<h4>Welcome</h4>
<p>Add Message</p>
</div>
</div>
</div>
</div>
</div>
<script type="text/javascript">
$('document').ready(function(){
$('#success').modal('toggle'); });
</script>
<?php
}else{
//action != joined do something
}
}else{
//$GET NOT set do something
}
选项3
Js警告
<?php
if(isset($_GET['action']) && !empty($_GET['action'])){
$action = $_GET['action'];
if($action == "joined"){?>
<script type="text/javascript">
alert('welcome');
</script>
<?php
}else{
//action != joined do something
}
}else{
//$GET NOT set do something
}
第一个选项，您需要根据您的设计需要设置pop / div的样式。
正如您所看到的，您需要首先检查网址中的操作是否已加入，这意味着他们已成功注册，然后显示弹出窗口
答案 1 :(得分：0)
您可以使用服务器端语言PHP使用$_GET['action']或$_REQUEST['action']正确返回标题 - index.php?action=joined
在数据库插入页面上创建逻辑，检查查询是否成功。成功时，它会将您路由到标题重定向，否则返回错误消息并退出脚本。
这样的事情：
$query = 'INSERT INTO members (username,password,email,active) VALUES (:username, :password, :email, :active)';
$stmt = $db->prepare($query);
$stmt->execute(array(
':username' => $_POST['username'],
':password' => $hashedpassword,
':email' => $_POST['email'],
':active' => $activasion
));
//Check to see if your $stmt is set, will return true if successful else it will return false
if($stmt){
$id = $db->lastInsertId('memberID');
//send email
$to = $_POST['email'];
$subject = "Registration Confirmation";
$body = "<p>Thank you for registering at Game World.</p>
<p>To activate your account, please click on this link: <a href='".DIR."activate.php?x=$id&y=$activasion'>".DIR."activate.php?x=$id&y=$activasion</a></p>
<p>Regards Site Admin</p>";
$mail = new Mail();
$mail->setFrom(SITEEMAIL);
$mail->addAddress($to);
$mail->subject($subject);
$mail->body($body);
$mail->send();
//redirect to index page
header('Location: index.php?action=joined');
}else{
echo 'Sorry but there was an issue with the INSERT.';
exit();
}
在index.php上使用if/else语句或switch来检查$_GET['action'] (isset)是否==为您的值'joined' }}。然后创建一个变量来保存欢迎消息并显示它，否则将变量声明为null或者发布备用消息。
index.php页面的顶部：
$message = "";
if(isset($GET['action']) && $GET['action']=="joined"){
//place your Welcome message here
$message .= "<h2>Welcome and thank you for signing up!</h2>";
}else{
$message .= "<h2>Some other message</h2>";
//Or you could go with empty quotes or declare $message NULL
}
然后在你的变量$ message的HTML调用中使用类似的东西：
<?=$message?>或<?php echo $message; ?>
<body>
<div id='wrapper'>
<header>Some header</header>
<nav id='nav'>
<ul>
<li class="nav-item">
<a href="#">BUTTON 1</a>
</li>
<li class="nav-item">
<a href="#">BUTTON 2</a>
</li>
</ul>
</nav>
<div id="content">
<?=$message?>
<div id="heading">Some Page Heading</div>
<div id="">
<p>
Some page content.
</p>
</div>
</div>
</div>
</body>
我不是最熟练的PHP，但这可能是我如何处理这样的服务器端请求。 ***请记住，您要求更新服务器页面，而不是按下按钮等客户端操作。
希望这有帮助。