如何查询值大于Oracle中表的最小值（值）的结果

Question

表A：

row_id     row_num
3488       1
3488       2
3488       3
4523       1
4523       2
8783       1
9999       2
9999       3
9999       4

如何得到我的表的结果，其中row_num应该大于row_num的最小值？ [例如row_num＆gt;分钟（ROW_NUM）]

预期结果

row_id     row_num
3488       2
3488       3
4523       2
9999       3
9999       4

Answer 1

使用min（）over（）

select row_id, row_num
from (
     select row_id, row_num, min(row_num) over() rm -- probably add partition by row_id
     from myTable
) t
where row_num > rm

Answer 2

使用ROWNUMBER和分区按RowIds进行分区，然后获得rownum＆gt; 1

;with cte
as
(select row_id,row_num,
row_number() over (partition by row_id order by row_num) as rownum
 from #temp
)
select row_id,row_num from cte where rownum>1