Question

我知道跟随FormulaArray是一条很长的路线。但我不知道如何解决这个问题，因为它显示Run-time error '1004': Unable to set the FormulaArray property of the Range class

Private Sub CommandButton2_Click()
Dim x As Variant
Dim y As Variant

Workbooks.Open (TextBox3.Text)

x = Split(TextBox2.Value, Application.PathSeparator)
y = Split(TextBox3.Value, Application.PathSeparator)

Workbooks(x(UBound(x))).Sheets("KomponentenohneDuplikate").Activate

Workbooks(x(UBound(x))).Sheets("KomponentenohneDuplikate").Range("y5").FormulaArray = "=iferror(INDEX('[" & y(UBound(y)) & "]Regelung&Partno'!C1:C10,MATCH(1,('[" & y(UBound(y)) & "]Regelung&Partno'!C5=RC[-24])*('[" & y(UBound(y)) & "]Regelung&Partno'!C9=""DC""),0),10),""-"")"
With Workbooks(x(UBound(x))).Sheets("KomponentenohneDuplikate").Range("y5:y3263")
.FillDown
.Value = .Value
End With

如果我写的公式没有`IFError（）＆＃39;然后它工作。这是下面给出的代码。

Workbooks(x(UBound(x))).Sheets("KomponentenohneDuplikate").Range("y5").FormulaArray = "=INDEX('[" & y(UBound(y)) & "]Regelung&Partno'!C1:C10,MATCH(1,('[" & y(UBound(y)) & "]Regelung&Partno'!C5=RC[-24])*('[" & y(UBound(y)) & "]Regelung&Partno'!C9=""DC""),0),10)"

但我的公式的问题是它返回＆＃34; #N / A＆＃34;在工作表'[" & y(UBound(y)) & "]Regelung&Partno'中找不到匹配时出错。所以我想用IfError()函数添加公式。但它不起作用

请帮我解决这个问题。

Answer 1

你好我在这里找到了我的问题的答案。我搜索了互联网并使用.Replace函数获得了正确的解决方案。

Dim FormulaPart1 As String
Dim FormulaPart2 As String
Dim FormulaPart3 As String
Dim origRS As Long

origRS = Application.ReferenceStyle
Application.ReferenceStyle = xlR1C1

FormulaPart1 = "=IFERROR(""Part2"",""-"")"
FormulaPart2 = "INDEX('[" & y(UBound(y)) & "]Regelung&Partno'!C1:C10,""Part3"",10)"
FormulaPart3 = "MATCH(1,('[" & y(UBound(y)) & "]Regelung&Partno'!C5=RC[-25])*('[" & y(UBound(y)) & "]Regelung&Partno'!C9=""Diverse""),0)"

With Workbooks(x(UBound(x))).Worksheets("KomponentenohneDuplikate").Range("z5")

.FormulaArray = FormulaPart1
.Replace what:="""Part2""", replacement:=FormulaPart2, lookat:=xlPart
.Replace what:="""Part3""", replacement:=FormulaPart3, lookat:=xlPart

End With
Application.ReferenceStyle = origRS

Arrayformula显示错误：无法设置范围类的formulaarray属性

1 个答案: