Question

我使用html，css，jquery和php制作页面，这里是登录功能，当我成功登录时，页面会显示我的用户名。但是当我刷新页面时，用户名变成＆＃34;登录＆＃34;。每次刷新时它都会自动注销吗？如何防止这种情况发生？我使用ajax将数据附加到html，如果设置会话我该怎么办？

LOGIN USERNAME

＆＃13;

<?php
   session_start();

   // include "maroon5/includes/dbh.php";
   define ("root",$_SERVER['DOCUMENT_ROOT']);// 
   include root."maroon5/includes/dbh.php";

   if(isset($_SESSION['id'])){
       // echo $_SESSION['id'];
      //WHAT SHOULD I DO HERE???
   }
   
?>
<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">
	<title>Maroon5 | Official Site</title>
	<link rel="stylesheet" type="text/css" href="styles/style.css">

＆＃13;

＆＃13; jquery的：

$(document).ready(function(){
$(document).on('click',"#submit",function(){
     var email = $("#edit-name").val();
     var pass  = $("#edit-pass").val();
     // alert (email);
     $.ajax({
        url:"functions/php/login.php",
        type:"POST",
        data:{ email:email,pass:pass},
        beforeSend: function () {

        },
        success:function(data){

            console.log(data);
            // alert(data);
            $("#edit-name").val(" ");
            $("#edit-pass").val(" ");
            // $("#user-login-register").hide();
            $("#popup-box1").hide();
            //
            $(".user-link-login").css({"display":"none"});
            $(".user-menu").append(data);
        },
        error: function(XMLHttpRequest, textStatus, errorThrown) {
             alert(XMLHttpRequest.status);
             alert(XMLHttpRequest.readyState);
             alert(textStatus);
        },
     });
     return false;
 });

});

PHP：

<?php

session_start();

error_reporting(E_ALL);
ini_set('display_errors',1);

define ("root",$_SERVER['DOCUMENT_ROOT']);
// echo root;
include root.'/maroon5/includes/dbh.php';
// var_dump($_REQUEST);

$email = $_POST['email'];
$pass = $_POST['pass'];

 $conn = mysqli_connect("localhost", "root", "", "maroon5");
 $sql = "SELECT * FROM user WHERE email= '$email' AND pass='$pass'  ";
$res = mysqli_query($conn, $sql);
$num = mysqli_num_rows($res);

$row = $res ->fetch_assoc();

if(!$email & !$pass){
    echo "All fields required";
 }elseif(!$email){
    echo "Email required";
 }elseif (!$pass) {
    echo "Password required";
 }elseif ($num == 0) {
    echo "wrong";
 }else{
    // echo "success";
    $_SESSION['id'] = $row['id'];
    ?>
     <li class="user-profile">
        <a class="" >
            <img src = "<?php echo $row["pic"] ?>" />
            <span class="user-username"><?php echo $row["username"];     ?></span>
        </a>
        <ul class="menu-dropdown">
            <li class="user-pro"><a  href="">VIEW PROFILE</a></li>
            <li class="user-verify-account"> <a class="user-parent-account" href=""><i class="fa fa-envelope-o" aria-hidden="true"></i>VERIFY ACCOUNT</a></li>
            <li class="user-logout"><a class="user-parent-logout" href=""><i class="fa fa-sign-out" aria-hidden="true"></i>LOGOUT</a></li>
        </ul>
    </li>

    <?php
 }

?>

Answer 1

也许尝试设置保存您的姓名或唯一ID的会话变量。这样，您可以在更轻松地刷新时重新加载信息。

刷新页面时如何防止注销？

1 个答案: