Question

我有下表。我从JSON获取此数据并将其存储到SQLite表中。我想从TABLE_MAC获取所有数据，其中meal_id = 12。

TABLE_MAC

| _id | meal_id |   name   |
----------------------------
|  1  | 12,16,17| mac veggi|
|  2  | 14,16   | mac allo |
|  3  | 16,12,14| mac egg  |
|  4  | 112,1,14| fries    |

现在，我想从数据库中获取来自meal_id = 12的所有数据。我已应用LIKE运算符从数据库中获取数据，但它在Android中添加了fries。

Answer 1

致电 LIKE 运营商

 public List<Model> getAllResult(String getId)
    {
        List<Model> resultList = new ArrayList<Model>();
        // Select All Query
       String selectQuery = "SELECT * FROM "+ TABLE_MAC + " WHERE " + KEY_Meal_ID + " LIKE '%"+getId+"%'";

        SQLiteDatabase db = this.getWritableDatabase();
        Cursor cursor = db.rawQuery(selectQuery, null);

        // looping through all rows and adding to list
        if (cursor.moveToFirst())
        {
            do {
                Model sg = new Model();
                sg.set_id((cursor.getString(0)));
                ......             

                resultList.add(sg);
            } while (cursor.moveToNext());

            cursor.close();
            db.close();
        }

        // return list
        return resultList;
    }

Answer 2

尝试这样的方法来查询数据库

    SQLiteDatabase database = this.getWritableDatabase();
    String[] columns = new String[] {"_id", "meal_id", "name"};
    String TABLE_NAME = "TABLE_MAC";
    Cursor mCursor =
            database.query(true, TABLE_NAME, columns,
                    "meal_id=12", null, null, null, null, null);
    if (mCursor != null) {
        mCursor.moveToFirst();
    }

然后，您必须循环浏览Cursor以检索您的数据。在您的meal_id列中使用逗号分隔ID并不是一个好主意。您应该实现映射表或重新考虑数据库以避免这种情况。

从SQLite数据库中返回行中的特定数据

2 个答案: