Question

在T-SQL中，我曾经能够做到以下几点：

delete t1
from table1 t1
join table2 t2 on t1.rowid = t2.rowid and t1.value <> t2.value

我希望能够在SAS中做同样的事情。

获取上面的代码并包装在proc sql中;并退出;抛出语法错误。

低于我的唯一选择？

proc sql;
delete from table1 t1
where t1.value <> (select t2.value from table2 t2 where t1.rowid = t2.rowid) 
and t1.rowid in (select t2.rowid from table t2);
quit;

谢谢。

Answer 1

所以你可能已经发现，删除效率不高。

如果你有磁盘空间，我建议你只根据内连接（你想要的记录）创建一个新表，drop table1，并重命名结果table1。

%let n=1000000;

data table1;
do rowid=1 to &n;
    value = rowid**2;
    output;
end;
run;

data table2;
do rowid=1 to &n;
    value = (mod(rowid,2)=1)*rowid**2;
    output;
end;
run;

proc sql noprint;
create table table1_new as
select a.*
    from table1 as a
      inner join
         table2 as b
      on a.rowid=b.rowid
       and 
         a.value = b.value;

drop table table1;

quit;

proc datasets lib=work nolist;
change table1_new = table1;
run;
quit;

删除连接表

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