Question

我正在使用ASP.NET MVC，我有一个存储过程的模型，我使用EF Designer从我现有的数据库创建。在这里，我把我的代码：

public class SpGetClientPhonesController : ApiController
{
   ShopEntities2 db = new ShopEntities2();
    public string Get()
    {
        var json = "";

        spGetRegister_Result objmodel = new spGetRegister_Result( *HERE I SHOULD SPECIFY THE SP INPUT PARAMETERS*);


    }
}

我想使用此模型来检索存储过程返回的数据，但我需要首先指定此存储过程所需的输入参数。我怎么能这样做？

Answer 1

如果您的模型是从数据库生成的，并且您在其中引用了存储过程。

然后，您使用Entity Framework调用存储过程的方式如下：

function computeLeftPoints() {
  var points = _points[_ikIndex];
  var distance = points[0].distance;
  var lock = points[0].lock;
  var angle;
  //var i;
  var iMod = 0;
  if (!lock) iMod = 1;

  for (let i = _pActive; i > 1 - iMod; i--) {
    points[i - 1].s = angle = Math.slope(points[i - 1], points[i]);

    points[i - 1].a = Math.angle(points[i - 2], points[i - 1], points[i]);
    points[i - 1].ap = anglePoint(points[i - 1]);

    if (i - 1 == 0) {
      angle = solve(points[i - 1], points[i], 'left');
    }
    points[i - 1].x = points[i].x + distance * Math.cos(angle); //Must be rounded unless will cause error in arc
    points[i - 1].y = points[i].y + distance * Math.sin(angle);
  }
  if (lock) {
    for (let i = 0; i < _pActive; i++) {
      points[i + 1].s = angle = Math.slope(points[i + 1], points[i]);

      points[i + 1].a = Math.angle(points[i + 2], points[i + 1], points[i]);
      points[i + 1].ap = anglePoint(points[i + 1]);

      if (i + 1 == 0) {
        angle = solve(points[i + 1], points[i], 'left lock');
      }
      points[i + 1].x = points[i].x + distance * Math.cos(angle);
      points[i + 1].y = points[i].y + distance * Math.sin(angle);
    }
  }
}

function computeRightPoints() {
  var points = _points[_ikIndex];
  var distance = points[0].distance;
  var lock = points[0].lock;
  var angle;
  var i;
  var iMod = 0;
  if (!lock) iMod = 1;

  for (i = _pActive; i < points.length - 2 + iMod; i++) {
    points[i + 1].s = angle = Math.slope(points[i + 1], points[i]);

    points[i + 1].a = Math.angle(points[i + 2], points[i + 1], points[i]);
    points[i + 1].ap = anglePoint(points[i + 1]);

    if (i + 1 == 0) {
      angle = solve(points[i + 1], points[i], 'right');
    }

    points[i + 1].x = points[i].x + distance * Math.cos(angle);
    points[i + 1].y = points[i].y + distance * Math.sin(angle);
  }
  if (lock) {
    for (i = points.length - 1; i > _pActive; i--) {
      points[i - 1].s = angle = Math.slope(points[i - 1], points[i]);

      points[i - 1].a = Math.angle(points[i - 2], points[i - 1], points[i]);
      points[i - 1].ap = anglePoint(points[i - 1]);

      if (i - 1 == 0) {
        angle = solve(points[i - 1], points[i], 'right lock');
      }

      points[i - 1].x = points[i].x + distance * Math.cos(angle); //Must be rounded unless will cause error in arc
      points[i - 1].y = points[i].y + distance * Math.sin(angle);
    }
  }
}

function solve(point, delta, LF) {
  if (!delta.out || !delta.in) return point.s;

  point.s = point.s > Math.radians(delta.in.value) + delta.s
    ? Math.radians(delta.in.value) + delta.s
    : point.s < delta.s - Math.radians(delta.out.value)
        ? delta.s - Math.radians(delta.out.value)
        : point.s;

  console.log(point.s);
  console.log(delta.s);
  console.log('Out: ' + (delta.s - Math.radians(delta.out.value)));
  console.log('In: ' + (Math.radians(delta.in.value) + delta.s));

  return point.s;// return slope
}

Answer 2

我正在挖掘并多问一点，我能够解决这个问题。使用实体框架将存储过程映射到模型时，您必须使用2个概念。使用我的prevoius示例和spGetRegister，当我创建模型时，我有spGetRegister和spGetRegister_Result。 spGetRegister_Result是处理Stored Procedure返回的内容的人，spGetRegister是我必须使用其输入参数调用的内容。这是一个例子：

ObjectResult<spGetRegister_Result> newRecord = new spGetRegister_Result;
newRecord = db.spGetRegister( IdClient:9587, IdSite:94);

从这里你可以在变量newRecord上得到存储过程的结果行，你可以用它做任何你想做的事。

Asp.Net将参数传递给实体框架中的存储过程MODEL

2 个答案: