Question

我需要获得符合两个标准的学生数量：

在最后3个学年时有3个顺序缺席，或者
在过去2个月内没有5次顺序缺席。

我有白天学生缺席的事实，其中包括以下字段：

StudentId
SchoolCalendarId
SchoolId
CLASSID
QtyAbsents（总是1，只是总和）

尺寸：

DimStudent
DimSchoolCalendar
DimSchool
DimClass

我做了一个MDX，返回符合第一个标准的学生名称：

WITH
    MEMBER [A] AS 
        CASE
            WHEN [Measures].[QtyLackingStudents] = 3 
            THEN 'THREE SEQUENCIAL ABSENTS' ELSE NULL END
SELECT
    NON EMPTY { [A] } ON COLUMNS,
    NON EMPTY { [DimStudent].[Name].ALLMEMBERS } ON ROWS
FROM
(
    SELECT
        ( FILTER(
            [DimSchoolCalendar].[Date].MEMBERS,
            [DimSchoolCalendar].[Date].CURRENTMEMBER.NAME = VBAMDX!Format(VBAMDX!Now(),"yyyy-MM-dd")
        ).ITEM(0).Lag(3):FILTER(
            [DimSchoolCalendar].[Date].MEMBERS,
            [DimSchoolCalendar].[Date].CURRENTMEMBER.NAME = VBAMDX!Format(VBAMDX!Now(),"yyyy-MM-dd")
        ).ITEM(0) ) ON COLUMNS
    FROM 
        (
            SELECT 
                ( { [DimSchoolCalendar].[SchoolDay].&[IsSchoolDay] } ) ON COLUMNS
            FROM [AlunosMatriculados]
        )
)

但我既不能做第二个标准，也不能把所有内容都放在一个单一的标准中。

修改

我制作了一个返回我想要的SQL。我需要MDX。

SELECT COUNT(DISTINCT f.StudentId)
FROM DW.FactLackingStudents f
    INNER JOIN DW.DimSchool e ON e.SchoolId = f.SchoolId
    INNER JOIN DW.DimSchoolCalendar ce ON ce.SchoolCalendarId = f.SchoolCalendarId
WHERE (SELECT COUNT(*) 
        FROM DM.FactLackingStudents f2
            INNER JOIN (
                SELECT c.SchoolCalendarId
                    , ROW_NUMBER() OVER(PARTITION BY c.Year, c.SchoolId ORDER BY c.Date DESC) AS Seq
                FROM dm.DimCalendarioEscolar c
                WHERE c.Year = a.Year
                    and c.SchoolKey = e.SchoolKey
                    and c.Date < GETDATE()
                    and c.SchoolDay = 'IS SCHOOL DAY'
            ) days ON days.SchoolCalendarId = f2.SchoolCalendarId
                and days.Seq <= 3
        WHERE f2.StudentId = f.StudentId) = 3   -- ABSENTS AT LAST 3 SCHOOL DAYS IS EQUAL 3
    OR 
    (
        SELECT COUNT(*) 
        FROM DM.FactLackingStudents f2
            INNER JOIN (
                SELECT c.SchoolCalendarId
                    , ROW_NUMBER() OVER(PARTITION BY c.Year, c.SchoolId ORDER BY c.Date DESC) AS Seq
                FROM dm.DimCalendarioEscolar c
                WHERE c.Year = a.Year
                    and c.SchoolKey = e.SchoolKey
                    and c.Date BETWEEN DATEADD(DD, -60, GETDATE()) AND GETDATE() -- LAST 2 MONTHS
                    and c.SchoolDay = 'IS SCHOOL DAY'
            ) days ON days.SKCalendarioEscolar = f2.SKDataInfrequencia
        WHERE f2.StudentId = f.StudentId
    ) >= 5  -- ABSENTS AT LAST 60 DAYS IS EQUAL 5

Answer 1

一步一步：

第一个标准

创建一个从开头到今天所有日子的日期集：

将该套装与IsSchoolDay交叉加入，以便仅限上学日：

{NULL:StrToMember('[DimSchoolCalendar].[Date].&[' + Format(Now(),'yyyy-MM-dd') + ']')}

从集合中获取最后三个成员：

[DimSchoolCalendar].[SchoolDay].&[IsSchoolDay] * {NULL:StrToMember('[DimSchoolCalendar].[Date].&[' + Format(Now(),'yyyy-MM-dd') + ']')}

创建计算度量：

Tail(               
    [DimSchoolCalendar].[SchoolDay].&[IsSchoolDay] * {NULL:StrToMember('[DimSchoolCalendar].[Date].&[' + Format(Now(),'yyyy-MM-dd') + ']')},
    3
)

第二个标准

获取当前月份：

SUM(    
    Tail(           
        [DimSchoolCalendar].[SchoolDay].&[IsSchoolDay] * {NULL:StrToMember('[DimSchoolCalendar].[Date].&[' + Format(Now(),'yyyy-MM-dd') + ']')},
        3
    ),
    [Measures].[QtyLackingStudents]
)

过去两个月：

StrToMember('[DimSchoolCalendar].[Month].&[' + Format(Now(),'yyyy-MM') + ']')

创建计算度量：

LastPeriods(
    2,
    StrToMember('[DimSchoolCalendar].[Month].&[' + Format(Now(),'yyyy-MM') + ']')
)

最终结果

SUM(    
    LastPeriods(
        2,
        StrToMember('[DimSchoolCalendar].[Month].&[' + Format(Now(),'yyyy-MM') + ']')
    ),
    [Measures].[QtyLackingStudents]
)

MDX - 如何根据事实表中存在的顺序天来计算维数？

1 个答案: