Question

我是stackoverflow的新手，并且有点困在我的Python任务上。

这就是问题：

编写一个程序MaximumScore.py，该程序会收到学生证，姓名和分数由学生获得。输出应显示最高分和获得该分数的学生最高分。

所需的输出如下所示：

Enter student id and score: 101, 89.5
Enter student name: Albert
Enter student id and score: 102, 92.5
Enter student name: Bill
Enter student id and score: 103, 95.5
Enter student name: Capa
Enter student id and score: 104, 79.5
Enter student name: Danny
Enter student id and score: 105, 90.5
Enter student name: Edgar

Maximum score: 95.5
Student id: 103
Student name: Capa

我的问题是如何获得获得最高分的家伙的身份证和姓名？我也不知道如何获得名单。我觉得我在这里缺少一些重要的东西。

到目前为止，这是我的代码：

def main():
 idnum = list()
 score= list()
 name=list()
 n =5
 for i in range(int(n)): idnum,score = input("Enter student id and score : ").split(",")

 print "Maximum Score ", max(score)

main()

Answer 1

您应该考虑使用dict而不是list。然后在dict {＆＃39; id＆＃39;：＆＃39;得分＆＃39;}您可以按ID排序和打印分数。使用你赢得的三个列表;能够将一个列表的元素与其他列表的元素连接起来。

在这种情况下阅读有关字典的python手册。它们是非常好的书面手册。

关于dict你可以使用ie dict={'id':['name','score']}所以key是学生ID，这个键的值将是名字和分数的列表。它很容易导航。

Answer 2

您可以使用Python的zip函数

idnum = []
score = []
name = []
n = 3

for i in range(n):
    id_score = input('Enter student id and score: ').split(',')
    idnum.append(id_score[0])
    score.append(id_score[1])
    name_ = input('Enter student name: ')
    name.append(name_)

save = zip(score,name,idnum)

for x in save:
    if max(score) in x:
        highest = x
        break
print('Maximum score: ' + highest[0])
print('Student id: ' + highest[2])
print('Student name: ' + highest[1])

Answer 3

您最好在一个列表中使用元组，并通过max中的键找到lambda值。

from collections import namedtuple

Student = namedtuple('Student', 'id name score')

def main():
    students = []
    n = 5
    for i in range(n):
        id, score = input('Enter student id and score: ').split(',')
        id = int(id)
        score = float(score)
        name = input('Enter student name: ')
        student = Student(id, name, score)
        students.append(student)
    student_max_score = max(students, key=lambda x: x.score)
    print('Max score: {}'.format(student_max_score.score),
          'Student id: {}'.format(student_max_score.id),
          'Student name: {}'.format(student_max_score.name),
          sep='\n')

main()

Answer 4

Wright几乎拥有它 - zip是一个很好用的工具，但你应该只使用max函数：

idnum = []
score = []
name = []
n = 3

for i in range(n):
    id, score = input('Enter student id and score: ').split(',')
    idnum.append(id)
    # If you don't convert to float it will
    # sort in ASCII order, which is not what you want
    score.append(float(score))
    name_ = input('Enter student name: ')
    name.append(name_)

highest = max(zip(score,name,idnum))

print('Maximum score: ' + highest[0])
print('Student id: ' + highest[2])
print('Student name: ' + highest[1])

在学生列表中创建并找到最高分？

4 个答案: