我正在尝试使用recursion-schemes
实现递归数据类型。我希望能够打印出来。
import Data.Functor.Foldable
data T1F a = Foo deriving Show
type T1 = Fix T1F
data T2 = Bar T1 deriving Show -- error here
错误讯息:
No instance for (Data.Functor.Classes.Show1 T1F)
arising from the first field of ‘Bar’ (type ‘T1’)
Possible fix:
use a standalone 'deriving instance' declaration,
so you can specify the instance context yourself
When deriving the instance for (Show T2)
如何T1
派生Show
?
答案 0 :(得分:3)
使用包deriving-compat
:
{-# LANGUAGE TemplateHaskell #-}
import Data.Functor.Foldable
import Text.Show.Deriving
data T1F a = Foo deriving Show
$(deriveShow1 ''T1F)
type T1 = Fix T1F
data T2 = Bar T1 deriving Show