如何将数组中的最终值拆分为自己的数组？

Question

我有一个数组数组，每个数组包含5个值。我想将整个数组中每个数组的最后一个值拆分为自己的数组，但我无法找到最佳方法。

-Dsun.security.krb5.debug=true

在这种情况下，数组中的最后一个值都是2，但情况并非总是如此。

我想得到这个：

FeatureVectors = [[4, 0.001743713493735165, 0.6497055601752815, 90.795723552739275, 2], [4, 0.0460937435599832, 0.19764217920409227, 90.204147248752378, 2], [1, 0.001185534503063044, 0.3034913722821194, 60.348908179729023, 2], [1, 0.015455289770298222, 0.8380914254332884, 109.02120657826231, 2], [3, 0.0169961646358455, 41.36919146079211, 136.83829993466398, 2]]

由于

Answer 1

使用以下方法（使用列表解析）：

FeatureVectors = [[4, 0.001743713493735165, 0.6497055601752815, 90.795723552739275, 2], [4, 0.0460937435599832, 0.19764217920409227, 90.204147248752378, 2], [1, 0.001185534503063044, 0.3034913722821194, 60.348908179729023, 2], [1, 0.015455289770298222, 0.8380914254332884, 109.02120657826231, 2], [3, 0.0169961646358455, 41.36919146079211, 136.83829993466398, 2]]
FeatureVectors, Labels = ([i[:-1] for i in FeatureVectors], [i[-1] for i in FeatureVectors])

print(FeatureVectors, Labels, sep='\n')

输出（连续）：

[[4, 0.001743713493735165, 0.6497055601752815, 90.79572355273928], [4, 0.0460937435599832, 0.19764217920409227, 90.20414724875238], [1, 0.001185534503063044, 0.3034913722821194, 60.34890817972902], [1, 0.015455289770298222, 0.8380914254332884, 109.02120657826231], [3, 0.0169961646358455, 41.36919146079211, 136.83829993466398]]
[2, 2, 2, 2, 2]

Answer 2

一次性完成：

Labels = [vector.pop() for vector in FeatureVectors]