Question

在我的应用程序中，我将图片存储为mysql db中的blob。现在我想在我的网络应用程序中显示图片。

现在的问题是：图像不会显示。只是一个小标志。我没有收到任何错误消息。

我不知道如何更新我的项目，以显示图片

模特功能：

public function create($fileName, $fileType, $fileSize, $fileContent, $gallery){
    $query = "INSERT INTO $this->tableName (name, type, size, content, gallery_ID) VALUES (?, ?, ?, ?, ?)";
    $statement = ConnectionHandler::getConnection()->prepare($query);
    $statement->bind_param('ssisi', $fileName, $fileType, $fileSize, $fileContent, $gallery);
    $success = $statement->execute();
    if (!$success) {
        throw new Exception($statement->error);
    }
}

public function listByID($galleryID){
    $query = "SELECT * from  $this->tableName where gallery_ID = ?";
    $statement = ConnectionHandler::getConnection()->prepare($query);
    $statement->bind_param('i', $galleryID);
    $statement->execute();

    $result = $statement->get_result();
    if (!$result) {
        throw new Exception($statement->error);
    }

    $rows = array();
    while ($row = $result->fetch_object()) {
        $rows[] = $row;
    }

    return $rows;
}

控制器方法：

public function doAddPhoto(){
    $fileName = $_FILES['fileToUpload']['name'];
    $fileSize = $_FILES['fileToUpload']['size'];
    $fileType = $_FILES['fileToUpload']['type'];
    $tmpName = $_FILES['fileToUpload']['tmp_name'];
    $gallery = $_SESSION['gallery'];

    $target_dir = "uploads/";
    $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
    $imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);

    if($_FILES['fileToUpload']['size'] <= 0 ){
        echo '<div class="alert alert-danger" id="messsage" role="alert">No Picture selected</div>';
    }
    else if ($_FILES["fileToUpload"]["size"] > 4194304) {
        echo '<div class="alert alert-danger" id="messsage" role="alert">File to big</div>';
    }
    else if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
        && $imageFileType != "gif" ) {
        echo '<div class="alert alert-danger" id="messsage" role="alert">Sorry, only JPG, JPEG, PNG & GIF files are allowed.</div>';
    }
    else {
        $fp = fopen($tmpName, 'r');
        $fileContent = fread($fp, filesize($tmpName));
        fclose($fp);

        if(!get_magic_quotes_gpc()){
            $fileName = addslashes($fileName);
        }



        $photoModel = new PhotoModel();
        $photoModel->create($fileName, $fileType, $fileSize, $fileContent, $gallery);

    }
    header('location: /gallery/ListGalleriesPerUserOverview');
}

public function showPhotosPerUser(){
    if (!isset($_SESSION ['loggedin']) || $_SESSION ['loggedin'] != true)
    { 
        header('location: /');
        return;
    }
    else{
        $view = new View('gallery');
        $galleryID = $_SESSION['gallery'];
        $photoModel = new PhotoModel($galleryID);
        $photos = $photoModel->listByID($galleryID);
        $view->photos = $photos;
        $view->display();
    }
}

HTML：

<form action="/photo/doAddPhoto" method="post" enctype="multipart/form-data">
      Select image to upload:
      <input type="file" name="fileToUpload" id="fileToUpload">

      <input type="submit" value="Upload Image" name="uploadBtn">
  </form>

<?php
        foreach ($photos as $photo){
            $content = $photo->content;
            echo '<div class="col-md-3 portfolio-item">
            <a href="#">
                <img src="data:image/jpeg;base64,'. base64_encode($content) .'" />

            </a>
        </div>';
        }
        ?>

我无法在php中显示mysql db中的blob图片

0 个答案: