Question

我正在运行Spring 4.3.7与Spring Security 4.2.2的组合，并使用Java配置进行配置，因此没有web.xml。现在我想获得一个自定义的404页面，如果无法解析页面，那么前面的方法似乎是覆盖了描述here和here的createDispatcherServlet方法。我想使用SimpleMappingExceptionResolver来处理它并返回我的自定义404页面，但抛出异常对我来说甚至都不起作用。我希望下面给出的配置足够了。

MvcWebApplicationInitializer.java

public class MvcWebApplicationInitializer
        extends AbstractAnnotationConfigDispatcherServletInitializer {

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class[] { AppConfig.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return null;
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/" };
    }

    @Override
    public void onStartup(ServletContext servletContext) throws ServletException {
        super.onStartup(servletContext);

        FilterRegistration.Dynamic filterRegistration = servletContext.addFilter("resourceUrlEncodingFilter",
                new ResourceUrlEncodingFilter());
        filterRegistration.setInitParameter("encoding", "UTF-8");
        filterRegistration.setInitParameter("forceEncoding", "true");
        filterRegistration.addMappingForUrlPatterns(null, true, "/*");
    }

    @Override
    protected DispatcherServlet createDispatcherServlet(WebApplicationContext servletAppContext)
    {
        DispatcherServlet dispatcherServlet = (DispatcherServlet) super.createDispatcherServlet(servletAppContext);
        dispatcherServlet.setThrowExceptionIfNoHandlerFound(true);
        return dispatcherServlet;
    }
}

AppConfig.java

@EnableWebMvc
@Configuration
@ComponentScan(...)
@EnableTransactionManagement
public class AppConfig extends WebMvcConfigurerAdapter {

    @Bean
    public InternalResourceViewResolver viewResolver() {
        InternalResourceViewResolver viewResolver
                = new InternalResourceViewResolver();
        viewResolver.setViewClass(JstlView.class);
        viewResolver.setPrefix("/WEB-INF/");
        viewResolver.setSuffix(".jsp");
        return viewResolver;
    }

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {

        [...]
    }

    @Autowired
    private RequestMappingHandlerAdapter requestMappingHandlerAdapter;
    @PostConstruct
    public void init() {
        requestMappingHandlerAdapter.setIgnoreDefaultModelOnRedirect(true);
    }

    @Bean(name = "simpleMappingExceptionResolver")
    public SimpleMappingExceptionResolver createSimpleMappingExceptionResolver() {
        SimpleMappingExceptionResolver exceptionResolver = new MappingExceptionResolver();

        Properties mappings = new Properties();
        mappings.setProperty("UserNotAccessibleException", "access");
        mappings.setProperty("VersionsModelCreationException", "versions");

        exceptionResolver.setExceptionMappings(mappings);
        exceptionResolver.setDefaultErrorView("index");
        exceptionResolver.setExceptionAttribute("exception");
        return exceptionResolver;
    }
[...]
}

我仍然只得到一个

 WARN in DispatcherServlet.java:noHandlerFound:1172: No mapping found for HTTP request with URI [/root/notexisting] in DispatcherServlet with name 'dispatcher'

而不是我可能使用SimpleMappingExceptionResolver处理的异常。有什么建议吗？

带有Java配置的Spring 4：覆盖createDispatcherServlet以使自定义404页面无法正常工作

0 个答案: