Question

我使用棘轮和symfony 2.8处理Web套接字应用程序以连接数据库并在某个列中更改值，如果有人连接到服务器，那么我应该注入服务并添加EntityManager $em 这样function __construct()，但问题是当我在Chat.php文件

上添加它时

public function __construct(EntityManager $em)

我收到此错误

  [Symfony\Component\Debug\Exception\FatalThrowableError]                      
  Type error: Argument 1 passed Chat::__construc t() must be an instance of Doctrine\ORM\EntityManager, none given, called in SocketCommand.php on line 41

此错误告诉我此行SocketCommand.php上存在问题

new Chat()

chat.php文件

<?php
namespace check\roomsBundle\Sockets;
use tuto\testBundle\Entity\Users;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Request;

use Ratchet\MessageComponentInterface;
use Ratchet\ConnectionInterface;
use Symfony\Component\DependencyInjection\ContainerInterface;
use Doctrine\ORM\EntityManager;
class Chat implements MessageComponentInterface  {
    //private $container;
    protected $clients;
    protected $em;
    //protected $db;
    public function __construct(EntityManager $em) {
        $this->clients = new \SplObjectStorage;
        //$this->container = $container;
        $this->em = $em;
    }

    public function onOpen(ConnectionInterface $conn) {
        $this->clients->attach($conn);

        echo "New connection! ({$conn->resourceId})\n";
        //$this->em->getRepository('yorrepo')->updateFuntion();
        $sql = $this->container->get('database_connection');
        $users = $sql->query("UPDATE user SET ONoroff= '1999' WHERE UserId='2'");


    }
}

SocketCommand.php代码

<?php
// myapplication/src/sandboxBundle/Command/SocketCommand.php
// Change the namespace according to your bundle
namespace check\roomsBundle\Command;

use Symfony\Component\Console\Command\Command;
use Symfony\Component\Console\Input\InputInterface;
use Symfony\Component\Console\Output\OutputInterface;

// Include ratchet libs
use Ratchet\Server\IoServer;
use Ratchet\Http\HttpServer;
use Ratchet\WebSocket\WsServer;

// Change the namespace according to your bundle
use check\roomsBundle\Sockets\Chat;

class SocketCommand extends Command
{
    protected function configure()
    {
        $this->setName('sockets:start-chat')
            // the short description shown while running "php bin/console list"
            ->setHelp("Starts the chat socket demo")
            // the full command description shown when running the command with
            ->setDescription('Starts the chat socket demo')
        ;
    }

    protected function execute(InputInterface $input, OutputInterface $output)
    {
        $output->writeln([
            'Chat socket',// A line
            '============',// Another line
            'Starting chat, open your browser.',// Empty line
        ]);

        $server = IoServer::factory(
            new HttpServer(
                new WsServer(
                    new Chat()
                )
            ),
            8080
        );

        $server->run();
    }
}

Answer 1

发生错误是因为您已将构造函数定义为：

public function __construct(EntityManager $em) {
    $this->clients = new \SplObjectStorage;
    //$this->container = $container;
    $this->em = $em;
}

那么你需要得到一个像这样的实体经理：

$em = $this->getDoctrine()->getManager();

然后在创建新对象时将其传递给：

new Chat( $em )

所以你需要弄清楚如何做到这一点。

类型错误：参数1传递Chat :: __ construc t（）必须是Doctrine \ ORM \ EntityManager的实例，没有给定，调用

1 个答案: