假设我有一个名为Build的表和一个名为Test的表。现在,对于每个构建,都有3个测试。表测试将build_id作为外键。此外,当测试失败时,我的测试框架会再次重试测试。鉴于此,测试表中至少有3个条目+更多基于测试失败的次数和重试的次数(最大值= 3)。此外,重试后,如果测试通过,则测试标记为已通过。
DATABASE
+----------+----------------------+
| title | date_issued |
+----------+----------------------+
| TITLE_1 | 2017-03-04 |
+----------+----------------------+
| TITLE_2 | 2017-03-17 |
+----------+----------------------+
| TITLE_3 | 2017-03-20 |
+----------+----------------------+
| TITLE_4 | 2017-04-01 |
+----------+----------------------+
AND I WANT TO BECOME WITH TO DISPLAY IN MY WEBSITE
**ARCHIVE MENU**
March 2017
April 2017
and so on...
现在,基于我想打印
Sample:
Build Table:
Id No of Tests Failure Count
1 3 0
2 3 0
3 3 1
Tests Table:
build_id test_id test_name test_result
1 1 test1 p
1 2 test2 p
1 3 test3 f
1 3 test3 f
1 3 test3 f
1 3 test3 p
2 1 test1 p
2 2 test2 p
2 3 test3 p
3 1 test1 p
3 2 test2 f
3 3 test3 p
2 2 test2 f
2 2 test2 f
2 2 test2 f
答案 0 :(得分:0)
如果我理解正确,您需要测试的次数" f":
select test_name, count(*) as retries
from tests
where test_result = 'f'
group by test_name;