Question

这是Json代码

{"data":{"user":{"first_name":"xx","last_name":"xx","email":"xx","countryOfResidence":"GB","country":"LK","nationality":"LK"},"billing_address":{"line1":"xx","city":"xx","postal_code":"xx","country":"LK"},"shipping_address":{"first_name":"xx","last_name":"xx","line1":"xx","city":"xx","postal_code":"xx","country":"LK"},"phone":{"type":"Mobile","number":"xx","countryCode":"94"},"marketing_optin":true,"shipping_address_validation":false,"poma_flow":false,"prox_flow":false,"testParams":{},"content_identifier":"LK:en:2.0.287:signupTerms.signupC","card":{"type":"MASTERCARD","number":"xx","security_code":"xx","expiry_month":"xx","expiry_year":"xx"},"skipInitiateAuth":true},"meta":{"token":"xx","calc":"xx","csci":"xx","locale":{"country":"LK","language":"en"},"state":"ui_checkout_guest","app_name":"xoonboardingnodeweb"}}

这是我希望以正确的方式编写代码并使其工作的PHP代码。我想知道我的错在哪里。任何人都可以更正此文件吗？请清楚地帮助这个例子。

                $link = "https://www.paypal.com/webscr?cmd=_express-checkout&token=EC-7Y207450BE832821N#/checkout/guest"; 
                $post = "";  
                $s = _curl($link, json_encode($post), $cookie);



            $post = json_encode($array);
            $array = json_decode($json_string, true);
$link = "https://www.paypal.com/webapps/xoonboarding/api/onboard/guest";


                                    $post = [
        'data' => [
            'user' => [
                'first_name' => 'xx',
                'last_name' => 'xx',
                'email' => 'xx',
                'countryOfResidence' => 'GB',
                'country' => 'LK',
                'nationality' => 'lk',
            ],
            'billing_address' => [
                'line1' => 'xx',
                'city' => 'xx',
                'postal_code' => 'xx',
                'country' => 'lk',
            ],
            'shipping_address' => [
                'first_name' => 'xx',
                'last_name' => 'xx',
                'line1' => 'xx',
                'city' => 'xx',
                'postal_code' => 'xx',
                'country' => 'lk',
            ],
            'phone' => [
                'type' => 'Mobile',
                'number' => 'xx',
                'countryCode' => '94',
            ],
            'marketing_optin' => true,
            'shipping_address_validation' => false,
            'poma_flow' => false,
            'prox_flow' => false,
            'testParams' => [],
            'content_identifier' => "LK:en:2.0.287:signupTerms.signupC",
            'card' => [
                'type' => 'xx',
                'number' => xx,
                'security_code' => xx,
                'expiry_month' => xx,
                'expiry_year' => xx,
            ],
            'skipInitiateAuth' => true
        ],
        'meta' => [
            'token' => xx,
            'calc' => xx,
            'csci' => xx,
            'locale' => [
                'country' => 'LK',
                'language' => 'en',
            ],
            'state' => 'ui_checkout_guest',
            'app_name' => 'xoonboardingnodeweb',
        ]
    ];

    $s = _curl($link, json_encode($post), $cookie);

Answer 1

您可以使用JSON Formatter轻松可视化JSON的结构，并将其转换为PHP。或者您可以创建一个PHP变量，这要归功于<iframe src="https://www.w3schools.com" width="80%" height="380px" scrolling="yes">和您在示例中给出的JSON代码。

＆＃13;

json_decode

＆＃13;

cod JSON to Array PHP我想要一个正确的例子

1 个答案: